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Q. No.A thin prism of refractive index \(\mu = 1.5\) introduces a deviation of \(+1^\circ\) into the path of an incident beam. When this prism is immersed in a liquid of refractive index \(\mu = 2\), the deviation introduced will be:
1.
\( \left ( \dfrac{7}{6} \right )^\circ\)
2.
\( \left ( \dfrac{3}{2} \right )^\circ\)
3.
\(- \left ( \dfrac{1}{2} \right )^\circ\)
4.
\( \left ( \dfrac{1}{2} \right )^\circ\)
Subtopic: Prisms |
60%
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Calculate the dispersive power of a thin prism from the following data:
1. \(0.04\)
2. \(0.02\)
3. \(25\)
4. \(50\)
| Colour | Deviation | ||
| Violet | \(2.04^\circ\) | ||
| Yellow | \(2.00^\circ\) | ||
| Red | \(1.96^\circ\) |
2. \(0.02\)
3. \(25\)
4. \(50\)
Subtopic: Prisms |
76%
From NCERT
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A parallel beam of light is incident onto a convex lens and after passing through the lens, it gets reflected from a plane mirror and passes through the lens again. The focal length of the lens is \(f.\) Where should the mirror be placed so that the final beam emerges parallel?
| 1. | Just behind the lens. |
| 2. | At the focus of the lens. |
| 3. | At a distance of \(2f\) from the lens. |
| 4. | At a distance of \(3f\) from the lens. |
Subtopic: Lenses |
68%
From NCERT
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An equiconvex lens of focal length \(50\) cm is made of glass of refractive index, \(\mu=1.5.\) It is split into two identical plano-convex lenses, and a glass-slab of the same refractive index, and of thickness \(300\) cm is inserted between the two half-lenses (plano-convex). When a parallel beam is incident on the combination, the emerging beam:
| 1. | focuses at a distance of \(100\) cm from the second lens. |
| 2. | focuses at \(200\) cm from second lens. |
| 3. | focuses at \(150\) cm from second lens. |
| 4. | emerges as a parallel beam. |
Subtopic: Lenses |
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An equiconvex lens of focal length \(100\) cm is split into two plano-convex lenses and the plane surface of one of these lenses is silvered. This acts as a:
| 1. | converging mirror of focal length \(200\) cm. |
| 2. | converging mirror of focal length \(100\) cm. |
| 3. | diverging mirror of focal length \(200\) cm. |
| 4. | diverging mirror of focal length \(100\) cm. |
Subtopic: Lenses |
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Two identical equilateral triangular prisms, each of which gives a minimum deviation of \(60^{\circ}\) are taken: call these prisms \(A,B\). These are placed as shown in the figure, and a ray of light is incident on prism \(A\) at minimum deviation. Now prism \(B\) is cut in half, along the dotted line, and the right half is removed. The deviation of the emerging ray is:
| 1. | \(90^{\circ}\) | 2. | \(45^{\circ}\) |
| 3. | \(60^{\circ}\) | 4. | \(30^{\circ}\) |
Subtopic: Prisms |
51%
From NCERT
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A thin plane parallel slab (thickness \(t\), refractive index \(\mu\)) is placed just behind a converging lens of focal length \(f.\) If a parallel beam of light is incident on the combination it will converge at a distance of:
| 1. | \(f\) from the end of the slab. |
| 2. | \(f-\frac{t}{\mu}\) from the end of the slab. |
| 3. | \(f+\frac{t}{\mu}\) from the end of the slab. |
| 4. | \(f+t\Big(1-\frac{1}{\mu}\Big)\) from the end of the slab. |
Subtopic: Refraction at Curved Surface |
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A convex lens of focal length \(60\) cm is placed in the path of a parallel beam, falling parallel to its principal axis. A plane mirror is placed on the principal axis, making an angle of \(45^{\circ}\) with it, at a distance of \(30\) cm behind the lens. The distance of the new focus from lens (optical centre) is:
1. \(60\) cm
2. \((60+30\sqrt2)\) cm
3. \(60\sqrt2\) cm
4. \(30\sqrt2\) cm
1. \(60\) cm
2. \((60+30\sqrt2)\) cm
3. \(60\sqrt2\) cm
4. \(30\sqrt2\) cm
Subtopic: Lenses |
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A parallel beam of width \(20\) mm is incident onto a lens and the width of the emerging beam decreases at a rate of \(1\) mm as it travels every \(3\) cm. The lens has a focal length of:
| 1. | \(30\) cm | 2. | \(60\) cm |
| 3. | \(\dfrac{20}3\) cm | 4. | \(\dfrac{40}{3}\) cm |
Subtopic: Lenses |
63%
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An empty cylindrical beaker whose height is equal to its diameter is kept on a table. An observer's eye\((E)\) looking towards \(S\) (line of sight: \(ES\)) can see the point \(Q\) on the lower right. The angle of view, \(\theta,\) is the angle the line of sight \(ES,\) makes with the vertical \(RS\)-extended. A transparent liquid is now slowly poured into the beaker. As the liquid level rises in the beaker, the line of sight has to be continually adjusted (by increasing angle \(\theta\)) in order to keep \(Q\) visible. When the liquid fills the beaker to the brim, \(Q\) can no more be seen by adjusting the line of sight \(ES. \) The minimum refractive index of the liquid should be:
| 1. | \(\dfrac32\) | 2. | \(2\) |
| 3. | \(\sqrt{\dfrac32} \) | 4. | \(\sqrt2\) |
Subtopic: Total Internal Reflection |
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