The loss in weight of a lead block is \(3\) times in liquid \(A\) compared to that in liquid \(B\). In both cases, the block is half immersed. If \(\rho_A, \rho_B\) be the densities of the liquids and \(\rho_L\) the density of lead, then:
1. | \(3\rho_A=\rho_B\) |
2. | \(\dfrac32\rho_A=\rho_B\) |
3. | \(\rho_A=\dfrac32\rho_B\) |
4. | \(\rho_A=3\rho_B\) |
A block of wood is immersed in water (assume that the wood is impervious to water), and it floats half immersed. It is placed in an elevator which is accelerating upward. Then,
1. | the block floats, slightly more of it out of the water. |
2. | the block floats, slightly less of it out of the water. |
3. | the block floats, half-immersed. |
4. | the block sinks completely. |
Given below are two statements:
Assertion (A): | Water flows through a smooth horizontal tube with a narrowing cross-section and its pressure increases. |
Reason (R): | Bernoulli's equation for fluids states that \(P+\dfrac{1}{2}\rho v^2+\rho gh= \) constant along a streamline. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | (A) is False but (R) is True. |
A small tube containing air at atmospheric pressure (\(P=76\) cm of Hg) has a mercury column of the length of \(19\) cm. The tube is initially horizontal, then it is turned so that the open end is upward and the tube is vertical.
The length of the trapped air column:
1. | \(10\) cm. | increases by
2. | \(10\) cm. | decrease by
3. | \(8\) cm. | increases by
4. | \(8\) cm. | decreases by
1. | \(\dfrac{4 F h}{A \rho g}\) | 2. | \(\dfrac{2 F h}{A \rho g}\) |
3. | \(\dfrac{F h}{A \rho g}\) | 4. | \(\dfrac{F h}{2 A \rho g}\) |
1. | rise. |
2. | sink. |
3. | float in the same position. |
4. | either rise or sink depending on the air pressure. |
1. | 2. | ||
3. | 4. |
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