The alkane that gives only one monochloro product on chlorination with \(\text{Cl}_2\) in presence of diffused sunlight is-

1.	2,2,-Dimethylbutane	2.	Neopentane
3.	n-Pentane	4.	Isopentane

In the following reaction,

\(\mathrm{ CH_{3}C\equiv CH\xrightarrow[Red \ hot \ iron \ tube]{873 K} \ A}\)

The number of ($\sigma$) bonds present in the product (A) is:

2,2–dimethylpropane, C(CH₃)₄, is an isomer of pentane, CH₃(CH₂)₃CH₃. Pentane has a boiling point of 36 °C whilst the boiling point of 2,2–dimethylpropane is 10 °C.

The statement that explains the difference in the boiling points for these two substances is: 

Which of the following would exhibit cis-trans isomerism?

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}={\mathrm{CH}}_2$

2. $\mathrm{ClCH}=\mathrm{CHCl}$

3. $\mathrm{ClCH}={\mathrm{CCl}}_2$

4. ${\mathrm{CH}}_2=\mathrm{CH}-\mathrm{COOH}$

In the following reaction,

the number of ($\sigma$) bonds present in the product (A) is-

The major product in the above-mentioned reaction is:

1.
2.
3.
4.

A compound of the formula ${\mathrm{C}}_4{\mathrm{H}}_8$ does not decolorize bromine water.  The compound can be:

1.  But-1-ene

2.  But-2-ene

3.  Cyclobutane

4.  2-methyl propene

Compound x and y respectively in the above reaction is: 

1.
2.
3.
4.

The major product (P), in the reaction given below, is:

1.		2.
3.		4.