A compound of the formula does not decolorize bromine water. The compound can be:
1. But-1-ene
2. But-2-ene
3. Cyclobutane
4. 2-methyl propene
Compound x and y respectively in the above reaction is:
1. | ![]() |
2. | ![]() |
3. | ![]() |
4. | ![]() |
Match the reagent from Column I which on reaction with CH3-CH=CH2 gives the same product given in Column II as per the codes given below
Column I | Column II | ||
A. | O3/Zn+H2O | 1. | Acetic acid and CO2 |
B. | KMnO4/H+ | 2. | Propan-1-ol |
C. | dil. KMnO4/OH- | 3. | Propane-1,2-diol |
D. | B2H6/NaOH+ and H2O2 | 4. | Acetaldehyde and formaldehyde |
Codes:
Options: | A | B | C | D |
1. | 4 | 1 | 3 | 2 |
2. | 1 | 2 | 3 | 4 |
3. | 1 | 4 | 3 | 2 |
4. | 4 | 1 | 2 | 3 |
Among the following reactions, incomplete combustion of methane is:
1. | \(2 \mathrm{CH}_4+\mathrm{O}_2 \xrightarrow[]{\mathrm{Cu/523 \ K/100 \ atm}} 2 \mathrm{CH}_3 \mathrm{OH}\) |
2. | \(\mathrm{CH}_4+\mathrm{O}_2 \xrightarrow[]{\mathrm{Mo_{2}O_{3}}} \mathrm{HCHO}+\mathrm{H}_2 \mathrm{O}\) |
3. | CH4 + O2 → C + 2H2O |
4. | CH4 + 2O2 → CO2 + 2H2O |
Assertion (A): | Eclipsed and staggered are two conformations of ethane. |
Reason (R): | In all the conformations, the bond angles and bond lengths change. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |
Four structures are given in options (a) to (d). Examine them and select the aromatic structures.
a. | ![]() |
b. | ![]() |
c. | ![]() |
d. | ![]() |
Choose the correct option
1. | (a, b) | 2. | (b, c) |
3. | (c, d) | 4. | (a, c) |
2,2–dimethylpropane, C(CH3)4, is an isomer of pentane, CH3(CH2)3CH3. Pentane has a boiling point of 36 °C whilst the boiling point of 2,2–dimethylpropane is 10 °C.
The statement that explains the difference in the boiling points for these two substances is:
1. | The molecules have different relative molecular masses. |
2. | Isomers have different chemical properties. |
3. | Pentane has permanent dipoles. |
4. | Longer chain, lesser branched molecules have stronger spontaneous/induced dipoles. |
Mark the correct order of reactivity towards the electrophilic aromatic substitution reaction.
1. | I > II > III > IV | 2. | IV > III > II > I |
3. | II > I > IV > III | 4. | II > I > III > IV |
In the following reaction,
the number of () bonds present in the product (A) is-
1. | 21 | 2. | 9 |
3. | 24 | 4. | 12 |
1. | |
2. | |
3. | |
4. |