In an experiment of \(\alpha\)-particle scattering by a gold foil (Geiger-Marsdon experiment), the\(\alpha\)-particles have kinetic energy \((KE=1.2\times 10^{-12}~\text J).\) What is the approximate distance of the closest approach of the \(\alpha\)-particles to the gold nuclei?
(take \(Z_\text{gold}=79\) )
1. \(3\times 10^{-14}~\text m\)
2. \(3\times 10^{-13}~\text m\)
3. \(3\times 10^{-12}~\text m\)
4. \(3\times 10^{-11}~\text m\)
Add Note
Subtopic: Â Various Atomic Models |
 70%
From NCERT
Other Reason
Highlight in NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Upgrade Your Plan
Upgrade now and unlock your full question bank experience with daily practice.