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Q. No.
Choose the incorrect statements regarding binding energy per nucleon:
1. Binding energy per nucleon is practically constant for nuclei with mass numbers between \(30\) and \(170\).
2. Binding energy per nucleon is maximum for \(_{56}\mathrm{Fe}\) (equal to \(8.75~\text{MeV}\)).
3. Binding energy per nucleon for \(_{6}\mathrm{Li}\) is lower compared to \(_{4}\mathrm{He}\).
4. Higher the binding energy per nucleon, the more unstable is the nucleus.
Subtopic:  Nuclear Binding Energy |
 74%
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In an exoergic nuclear reaction (i.e. energy is released in the reaction), let
1. \(E_1\): total binding energy of initial nuclei
2. \(E_2\): total binding energy of final nuclei
3. \(A_1\): total number of nucleons of initial nuclei
4. \(A_2\): total number of nucleons of final nuclei
Then:
1. \(E_1>E_2\)
2. \(E_2>E_1\)
3. \(E_1=E_2\)
4. \(\dfrac{E_1}{A_1}=\dfrac{E_2}{A_2}\)
Subtopic:  Nuclear Binding Energy |
 52%
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Let the average nuclear force exerted by a proton on a proton be \(\mathrm{F_{pp}}\), by a proton on a neutron be \(\mathrm{F_{pn}}\) and by a neutron on a neutron be \(\mathrm{F_{nn}}\). When their separations are nearly \(1~\text{fm}\), then,
1. \( \mathrm{F}_{\mathrm{pp}}<\mathrm{F}_{\mathrm{pn}}<\mathrm{F}_{\mathrm{nn}} \) 2. \( \mathrm{F}_{\mathrm{pn}}>\mathrm{F}_{\mathrm{pp}}>\mathrm{F}_{\mathrm{nn}} \)
3. \( \mathrm{F}_{\mathrm{pp}}>\mathrm{F}_{\mathrm{pn}}>\mathrm{F}_{\mathrm{nn}} \) 4. \(\mathrm{F}_{\mathrm{pp}}=\mathrm{F}_{\mathrm{pn}}=\mathrm{F}_{\mathrm{nn}}\)
Subtopic:  Nuclear Binding Energy |
 75%
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Given below are two statements:
Assertion (A): Binding energy per nucleon for nuclei (atomic number \(30\) to \(107\)) is independent of atomic number.
Reason (R): Nuclear force is short-range force.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Nuclear Binding Energy |
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The strong nuclear force between two nucleons:
1. is only attractive force.
2. is only repulsive force.
3. maybe attractive or repulsive in nature depending on the distance.
4. is a central force.
Subtopic:  Nuclear Binding Energy |
 56%
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A force that holds two protons by the same force as the force between two neutrons in a nucleus is:
1. An electric force
2. Weak nuclear force
3. Strong nuclear force
4. Gravitational force
Subtopic:  Nuclear Binding Energy |
 82%
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For the given radioactive decay reaction:
\(^{298}_{94}X \rightarrow ^{294}_{92}Y + { ^{4}_{2}\alpha} + Q\text-\text {value}\),
where the binding energy per nucleon of \(X,Y \) and \(\alpha\) are denoted by \(a, b \) and \(c\) respectively.
The expression for the \(Q\)-value is:
1. \((294 b +4c - 298 a)\)
2. \((92 b +2c - 94 a)\)
3. \((294 b +4c + 298 a)\)
4. \((92 b +2c + 94 a)\)
Subtopic:  Nuclear Binding Energy |
 84%
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We are given the following atomic masses:
\({ }_{92}^{238} \mathrm{U}=238.05079~\text{u},{ }_2^4 \mathrm{He}=4.00260~\text{u} \\ { }_{90}^{234} \mathrm{Th}=234.04363~\text{u},{ }_1^1 \mathrm{H}=1.00783~\text{u}\\ { }_{91}^{237} \mathrm{~Pa}=237.05121~\text{u} \)
Here the symbol \(\mathrm{Pa}\) is for the element protactinium \((Z=91)\).
The energy released during the alpha decay of \({}^{238}_{92}\mathrm{U}\) is:
1. \(6.14~\text{MeV}\)
2. \(7.68~\text{MeV}\)
3. \(4.25~\text{MeV}\)
4. \(5.01~\text{MeV}\)

Subtopic:  Nuclear Binding Energy |
 50%
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We are given the following atomic masses:
\({ }_{92}^{238} \mathrm{U}=238.05079~\text{u},{ }_2^4 \mathrm{He}=4.00260~\text{u} \\ { }_{90}^{234} \mathrm{Th}=234.04363~\text{u},{ }_1^1 \mathrm{H}=1.00783~\text{u}\\ { }_{91}^{237} \mathrm{~Pa}=237.05121~\text{u} \)
Here the symbol Pa is for the element protactinium \((Z=91)\).
Then:

1. \({}_{92}^{238}\mathrm{U}\) can not spontaneously emit a proton.
2. \({}_{92}^{238}\mathrm{U}\) can spontaneously emit a proton.
3. The \(Q\text-\)value of the process is negative.
4. Both (1) and (3) are correct.
Subtopic:  Nuclear Binding Energy |
 62%
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