In a metre bridge, there is an error due to excess resistance at the ends \(A\) & \(B.\) Due to this, the correct expression to be used is:
\(\dfrac PQ=\dfrac{\theta_A+l}{(100-l)+\theta_B},\)
where \(l\) is the measured balance length & \(\theta_A,\theta_B\) are the respective "end corrections". In the metre bridge shown in the figure, the following data was collected.
\(P\) \(Q\) \(l\)
\(100~\Omega\) \(100~\Omega\) \(50~\text{cm}\)
\(42~\Omega\) \(60~\Omega\) \(41~\text{cm}\)
\(240~\Omega\) \(x~\Omega\) \(79~\text{cm}\)
\(\theta_A,\theta_B\) are to be determined from the first two sets of data & then it has to be used to find the unknown resistance \(x~(\Omega).\)
From the data, it can be concluded that:
1. \(\theta_A=\theta_B\)
2. \(\theta_A=2\theta_B\)
3. \(\theta_B=2\theta_A\)
4. \(\theta_A=-\theta_B\)
Subtopic:  Meter Bridge |
 87%
From NCERT
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In a metre bridge, there is an error due to excess resistance at the ends \(A\) & \(B.\) Due to this, the correct expression to be used is:
\(\dfrac PQ=\dfrac{\theta_A+l}{(100-l)+\theta_B},\)
where \(l\) is the measured balance length & \(\theta_A,\theta_B\) are the respective "end corrections". In the metre bridge shown in the figure, the following data was collected.
\(P\) \(Q\) \(l\)
\(100~\Omega\) \(100~\Omega\) \(50~\text{cm}\)
\(42~\Omega\) \(60~\Omega\) \(41~\text{cm}\)
\(240~\Omega\) \(x~\Omega\) \(79~\text{cm}\)
\(\theta_A,\theta_B\) are to be determined from the first two sets of data & then it has to be used to find the unknown resistance \(x~(\Omega).\)
The value of \(\theta_A,\) from the data, is:
1. \(1~\text{cm}\)
2. \(0.5~\text{cm}\)
3. \(2~\text{cm}\)
4. \(-1~\text{cm}\)
Subtopic:  Meter Bridge |
 81%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch


In a metre bridge, there is an error due to excess resistance at the ends \(A\) & \(B.\) Due to this, the correct expression to be used is:
\(\dfrac PQ=\dfrac{\theta_A+l}{(100-l)+\theta_B},\)
where \(l\) is the measured balance length & \(\theta_A,\theta_B\) are the respective "end corrections". In the metre bridge shown in the figure, the following data was collected.
\(P\) \(Q\) \(l\)
\(100~\Omega\) \(100~\Omega\) \(50~\text{cm}\)
\(42~\Omega\) \(60~\Omega\) \(41~\text{cm}\)
\(240~\Omega\) \(x~\Omega\) \(79~\text{cm}\)
\(\theta_A,\theta_B\) are to be determined from the first two sets of data & then it has to be used to find the unknown resistance \(x~(\Omega).\)
The value of the unknown resistance \((x)\) is:
1. \(63~\Omega\)
2. \(66~\Omega\)
3. \(60~\Omega\)
4. \(64~\Omega\)
Subtopic:  Meter Bridge |
 67%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

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