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Q. No.Two particles of masses \(M,m\) are separated by a distance \(r.\) Their relative acceleration due to their mutual gravitational forces is (of magnitude):
| 1. | \(\Large\frac{2GMm}{r^2(M+m)}\) | 2. | \(\Large\frac{GMm}{r^2(M+m)}\) |
| 3. | \(\Large\frac{G(M\text - m)}{r^2}\) | 4. | \(\Large\frac{G(M\text + m)}{r^2}\) |
Subtopic: Â Acceleration due to Gravity |
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If a particle is projected vertically upward with a speed \(u,\) and rises to a maximum altitude \(h\) above the earth's surface then:
(\(g=\) acceleration due to gravity at the surface)
| 1. | \(h>\dfrac{u^2}{2g}\) |
| 2. | \(h=\dfrac{u^2}{2g}\) |
| 3. | \(h<\dfrac{u^2}{2g}\) |
| 4. | Any of the above may be true, depending on the earth's radius |
Subtopic: Â Acceleration due to Gravity |
From NCERT
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Consider the earth to be a uniform solid sphere of radius \(R,\) and take the acceleration due to gravity to be \(g,\) on its surface. Ignore the rotation of the earth. At what distance from the surface of the earth will the gravitational acceleration fall to \(\Large\frac{g}{9}\small,\) outside?
| 1. | \(\dfrac{R}{3}\) | 2. | \(3R\) |
| 3. | \(\dfrac{2R}{3}\) | 4. | \(2R\) |
Subtopic: Â Acceleration due to Gravity |
 68%
From NCERT
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