- 1(current)
Q. No.A small block of mass \(m\) slides a distance \(L\) down a smooth incline and rebounds elastically back up. The period of the motion is: (using standard symbols where necessary)
1. \(\Large\sqrt{\frac{4L\sin\theta}{g}}\)
2. \(\Large\sqrt{\frac{8L\sin\theta}{g}}\)
3. \(\Large\sqrt{\frac{8L}{g\sin\theta}}\)
4. \(\Large\sqrt{\frac{4L}{g\sin\theta}}\)
1. \(\Large\sqrt{\frac{4L\sin\theta}{g}}\)
2. \(\Large\sqrt{\frac{8L\sin\theta}{g}}\)
3. \(\Large\sqrt{\frac{8L}{g\sin\theta}}\)
4. \(\Large\sqrt{\frac{4L}{g\sin\theta}}\)
Subtopic: Â Linear SHM |
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A particle moves in the x-y plane according to the equation
\(x = A \cos^2 \omega t\) and \(y = A \sin^2 \omega t\)
Then, the particle undergoes:
| 1. | uniform motion along the line \(x + y = A\) |
| 2. | uniform circular motion along \(x^2 + y^2 = A^2\) |
| 3. | SHM along the line \(x + y = A\) |
| 4. | SHM along the circle \(x^2 + y^2 = A^2\) |
Subtopic: Â Linear SHM |
From NCERT
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The equation of motion of a particle that starts moving at \(t=0\) s is given by \({x}=5 \sin \left(\dfrac{\pi t}{2}+\dfrac{\pi}{3}\right) \) where \(x\) is in cm and time \(t\) is in second. The time, when the particle first comes to rest, is:
| 1. | \(\dfrac{1}{3}\) s | 2. | \(\dfrac{7}{6}\) s |
| 3. | \(\dfrac{2}{3}\) s | 4. | \(\dfrac{13}{6}\) s |
Subtopic: Â Linear SHM |
 63%
From NCERT
To view explanation, please take trial in the course.
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Hints
To view explanation, please take trial in the course.
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