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Q. No.A block of mass \(1\) kg is suspended by means of a spring, and the system is at rest. An additional force is now applied to the block and it accelerates downward at '\(g\)' \((g =10~\text{m/s}^2)\). At this moment, the force exerted by the spring on the block will be:
1. \(10~\text{N}\)
2. \(15~\text{N}\)
3. \(20~\text{N}\)
4. zero
Subtopic: Â Spring Force |
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The system is at rest initially, due to the force of friction acting on \(A\). If the string connecting the lower blocks is cut, the accelerations of the blocks \(A\), \(B\) & \(C\) will be, respectively,
| 1. | \(\dfrac g 3\) to left, \(g\) upward, \(g\) downward. |
| 2. | zero, zero, \(g\) downward. |
| 3. | zero, \(g\) upward, \(g\) downward. |
| 4. | \(g\) to right, zero, \(g\) downward. |
Subtopic: Â Spring Force |
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A block of mass \(m\) is placed between two springs connected to the ends of a railroad car. The surface supporting the block is horizontal, and the spring are initially relaxed. The car is given an acceleration \(a\) and the mass \(m\) finally comes to equilibrium within the car. Let \(x\) be the compression (or extension) in the two springs. Assume friction to be negligible. Then:
| 1. | \(k_1x-k_2x=ma \) |
| 2. | \(\dfrac{k_1k_2}{k_1+k_2}x=ma \) |
| 3. | \(k_1x+k_2x=ma \) |
| 4. | \(\dfrac{k_1k_2}{k_1-k_2}=ma \) |
Subtopic: Â Spring Force |
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Two \(1~\text{kg}\) blocks are connected by a light inextensible string and the system is suspended by a spring of stiffness \(1000~\text{N/m}.\) Take \(g=10~\text{m/s}^2.\)
The extension in the spring, in equilibrium, is:
1. \(1~\text{cm}\)
2. \(2~\text{cm}\)
3. \(0.5~\text{cm}\)
4. \(\sqrt2~\text{cm}\)
The extension in the spring, in equilibrium, is:
1. \(1~\text{cm}\)
2. \(2~\text{cm}\)
3. \(0.5~\text{cm}\)
4. \(\sqrt2~\text{cm}\)
Subtopic: Â Spring Force |
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