The brown ring test for NO3- is enabled due to the formation of the complex ion with the formula:
1. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} \)
2. \(\mathrm{Fe}\left[\mathrm{NO}(\mathrm{CN})_5\right]^{2-} \)
3. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right]^{2+} \)
4. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)(\mathrm{NO})_5\right]^{2+} \)
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Sodium nitroprusside, when added to an alkaline solution of sulphide ions, produces purple colour ion due to formation of:
1. \(Na[Fe(H_2O)_5NOS]2 \)
2. \(Na_2[Fe(H_2O)_5NOS] \)
3. \(Na_3[Fe(CN)_5NOS] \)
4. \(Na_4[Fe(CN)_5NOS] \)
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Two test tubes containing nitrate and bromide are treated separately with conc. H2SO4. Brown fumes, thus evolved, are passed in water. The water will be coloured by vapours evolved from the test tube containing:
1. Nitrate
2. Bromide
3. Both (a) and (b)
4. None of these
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The solution of a chemical compound (X) reacts with \(AgNO_3\) solution to form a white precipitate of (Y) which in turn dissolves in \(NH_4OH \) to give a complex (Z). When (Z) is treated with dilute \(HNO_3,\) (Y) reappears. The chemical compound X can be :
1. \(NaCl \)
2. \(CH_3Cl \)
3. \(NaBr \)
4. \(NaI \)
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Subtopic: Ā Detection of the functional groups |
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When dil. H2SO4 is introduced to an inorganic mixture at a low temperature, an odourless, colourless gas is produced. The mixture includes:
1. Sulphite
2. Acetate
3. Nitrite
4. Carbonate
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When bismuth chloride is poured into a large volume of water, the formula for the white precipitate produced is:
1. \(Bi(OH)_3\)
2. \(Bi_2O_3 \)
3. \(BiOCl \)
4. \(Bi_2OCl \)
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Subtopic: Ā Detection of Cations |
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A gas (X) is passed through water to form a saturated solution. The aqueous solution on treatment with silver nitrate gives a white precipitate. The saturated aqueous solution also dissolves magnesium ribbon with the evolution of a colourless gas (Y). X and Y, respectively, are:
1. \(X= CO_2,~Y=Cl_2 \)
2. \(X= Cl_2,~Y=CO_2 \)
3. \(X= Cl_2,~Y=H \)
4. \(X= H,~Y=Cl_2 \)
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