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Q. No.The second law of thermodynamics says:
1.
the efficiency of a heat engine can be unity.
2.
the heat released to the cold reservoir can be made zero.
3.
coefficient of performance can never be infinite for refrigerators.
4.
none of the above.
Subtopic: Second Law of Thermodynamics |
61%
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The lowest possible temperature is:
| 1. | \(0^\circ\text{C}\) | 2. | \(0^\circ \text{F}\) |
| 3. | \(-173^\circ \text{C}\) | 4. | \(0 ~\text{K}\) |
Subtopic: Second Law of Thermodynamics |
80%
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Consider the following reaction:
\(\mathrm{2H_2(g) + O_2(g) \rightarrow 2H_2O(g) \Delta_rH^\circ = -483.64 kJ. }\)
What is the enthalpy change for the decomposition of one mole of water?
\(\mathrm{2H_2(g) + O_2(g) \rightarrow 2H_2O(g) \Delta_rH^\circ = -483.64 kJ. }\)
What is the enthalpy change for the decomposition of one mole of water?
| 1. | 120.9 kJ | 2. | 241.82 kJ |
| 3. | 18 kJ | 4. | 100 kJ |
Subtopic: Thermochemistry |
88%
From NCERT
NEET - 2023
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NEET 2025 - Target Batch
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NEET 2025 - Target Batch
Three thermochemical equations are given below:
Based on the above equations, find out which one of the relationships given below is correct :
| (i) | C(graphite) + O2(g) \(\rightarrow\) CO2(g); \(\Delta_{r}\)H° = x kJ mol–1 |
| (ii) | Cgraphite + 1/2 O2(g) \(\rightarrow\) CO(g); \(\Delta_{r}\)H° = y kJ mol–1 |
| (iii) | CO(g) + 1/2 O2(g) \(\rightarrow\) CO2(g); \(\Delta_{r}\)H° = z kJ mol–1 |
Based on the above equations, find out which one of the relationships given below is correct :
| 1. | z = x + y | 2. | x = y + z |
| 3. | y = 2z – x | 4. | x = y – z |
Subtopic: Hess's Law |
79%
From NCERT
NEET - 2013
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NEET 2025 - Target Batch
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NEET 2025 - Target Batch
The \((P\text-V)\) diagram of a gas system undergoing a cyclic process is shown in the given figure. The work done by the gas during isobaric compression is:
1. \(150~\text J\)
2. \(-200~\text J\)
3. \(-400~\text J\)
4. \(-250~\text J\)
1. \(150~\text J\)
2. \(-200~\text J\)
3. \(-400~\text J\)
4. \(-250~\text J\)
Subtopic: Cyclic Process |
59%
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The temperature of \(n\) moles of an ideal gas is increased from \(T\) to \(4T\) through a process for which pressure \(P=\frac aT,\) where \(a\) is a constant. The work done by the gas is: (\(R\) is universal gas constant)
| 1. | \(3nRT\) | 2. | \(6nRT\) |
| 3. | \(4nRT\) | 4. | \(9nRT\) |
Subtopic: Work Done by a Gas |
From NCERT
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One mole of an ideal gas at 300 K is expanded isothermally from 1 L to 10 L volume. \(\Delta U\) for this process is:
(Use R = 8.314 J K–1 mol–1)
(Use R = 8.314 J K–1 mol–1)
| 1. | 1260 J | 2. | 2520 J |
| 3. | 5040 J | 4. | 0 J |
Subtopic: First Law of Thermodynamics |
80%
From NCERT
NEET - 2022
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NEET 2025 - Target Batch
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A thermally insulated vessel contains an ideal gas of molecular mass \(M\) and a specific heat ratio of \(1.4.\) The vessel is moving with speed \(v\) and is suddenly brought to rest. Assuming no heat is lost to the surroundings, then the vessel temperature of the gas increases by:
(\(R=\) universal gas constant)
1. \(\dfrac{M v^2}{7 R} \)
2. \(\dfrac{M v^2}{5 R} \)
3. \(\dfrac{2M v^2}{7 R} \)
4. \(\dfrac{7M v^2}{5 R} \)
(\(R=\) universal gas constant)
1. \(\dfrac{M v^2}{7 R} \)
2. \(\dfrac{M v^2}{5 R} \)
3. \(\dfrac{2M v^2}{7 R} \)
4. \(\dfrac{7M v^2}{5 R} \)
Subtopic: Molar Specific Heat |
56%
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A monoatomic gas performs a work of \(\dfrac{ Q} {4}\) where \(Q\) is the heat supplied to it. During this transformation, the molar heat capacity of the gas will be: (\(R\) is the gas constant.)
| 1. | \(R\) | 2. | \(2R\) |
| 3. | \(3R\) | 4. | \(4R\) |
Subtopic: Molar Specific Heat |
59%
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A heat engine (Carnot engine) operates between a cold reservoir at temperature \(T_2=300\) K and a hot reservoir at temperature \(T_1.\) If it were to take \(100\) J of heat from the hot reservoir and deliver \(80\) J of heat to the cold reservoir in each cycle, the minimum temperature of the hot reservoir would be:
1. \(350\) K
2. \(375\) K
3. \(400\) K
4. \(450\) K
1. \(350\) K
2. \(375\) K
3. \(400\) K
4. \(450\) K
Subtopic: Carnot Engine |
87%
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