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Q. No.Arrange the following in increasing order of stability:
(a)
\(\left(\mathrm{CH}_3\right)_2 \stackrel{\oplus}{\mathrm{C}}-\mathrm{CH}_2-\mathrm{CH}_3 \)
(b)
\(\left(\mathrm{CH}_3\right)_3 \stackrel{\oplus}{\mathrm{C}} \)
(c)
\(\left(\mathrm{CH}_3\right)_2 \stackrel{\oplus}{\mathrm{C}}\mathrm{H} \)
(d)
\( \text {CH}_3 \stackrel{\oplus}{\mathrm{C}}\mathrm{H}_2\)
(e)
\( \stackrel{\oplus}{\mathrm{C}}\mathrm{H}_3 \)
1.
e < d < c < a < b
2.
d < e < c < a < b
3.
a < e < d < c < b
4.
e < d < c < b < a
Subtopic: Reaction Intermediates ; Preparation & Properties |
75%
From NCERT
NEET - 2013
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is:
Subtopic: Hybridisation & Structure of Carbon Compounds |
85%
From NCERT
NEET - 2013
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Subtopic: Aromaticity & Polarity |
84%
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NEET - 2013
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Nitrogen detection in an organic compound is carried out by Lassaigne's test. The blue colour formed corresponds to which of the following formulae:
1. \(\mathrm{Fe_3[Fe(CN)_6]_2}\)
2. \(\mathrm{Fe_4[Fe(CN)_6]_3}\)
3. \(\mathrm{Fe_4[Fe(CN)_6]_2}\)
4. \(\mathrm{Fe_3[Fe(CN)_6]_3}\)
1. \(\mathrm{Fe_3[Fe(CN)_6]_2}\)
2. \(\mathrm{Fe_4[Fe(CN)_6]_3}\)
3. \(\mathrm{Fe_4[Fe(CN)_6]_2}\)
4. \(\mathrm{Fe_3[Fe(CN)_6]_3}\)
Subtopic: Qualitative Analysis of Organic Compounds |
77%
From NCERT
NEET - 2013
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\(\mathrm{CH_3-CH_3, \ CH_3-CH_2-CH_3, \ }\)
\(\mathrm{\left(CH_3\right)_2 CH-CH_3, }\) and \(\mathrm{CH_3-CH_2-CH\left(CH_3\right)_2 }\)
The increasing order of stability of the free radicals formed from homolytic fission of the above three alkanes is:
| 1. | \(\mathrm{ (CH_3)_2 \dot{C}-CH_2 CH_3<CH_3-\dot{C} H-CH_3 \\ <CH_3-\dot{C} H_2<(CH_3)_3 \dot{C} }\) |
| 2. | \( \mathrm{CH_3-\dot{C} H_2<CH_3-\dot{C} H-CH_3 \\ <\left(CH_3\right)_2 \dot{C}-CH_2 CH_3<\left(CH_3\right)_3 \dot{C}}\) |
| 3. | \(\mathrm{CH_3-\dot{C} H_2<CH_3-\dot{C} H-CH_3\\ <\left(CH_3\right)_3 \dot{C}<\left(CH_3\right)_2 \dot{C}-CH_2 CH_3 }\) |
| 4. | \(\mathrm{ \left(CH_3\right)_3 \dot{C}<\left(CH_3\right)_2 \dot{C}-CH_2-CH_3 \\ <CH_3-\dot{C} H-CH_3<CH_3-\dot{C} H_2 }\) |
Subtopic: Reaction Intermediates ; Preparation & Properties |
79%
From NCERT
NEET - 2013
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The outer orbitals of C in an ethene molecule can be considered to be hybridized to given three equivalent sp2 orbitals. The total number of sigma (\(\sigma\)) and pi(\(\pi\)) bonds in ethene molecule are:
1. 3 sigma (\(\sigma\)) and 2 pi(\(\pi\)) bonds
2. 4 sigma (\(\sigma\)) and 1 pi(\(\pi\)) bonds
3. 5 sigma (\(\sigma\)) and 1 pi(\(\pi\)) bonds
4. 1 sigma (\(\sigma\)) and 2 pi(\(\pi\)) bonds
1. 3 sigma (\(\sigma\)) and 2 pi(\(\pi\)) bonds
2. 4 sigma (\(\sigma\)) and 1 pi(\(\pi\)) bonds
3. 5 sigma (\(\sigma\)) and 1 pi(\(\pi\)) bonds
4. 1 sigma (\(\sigma\)) and 2 pi(\(\pi\)) bonds
Subtopic: Hybridisation & Structure of Carbon Compounds |
86%
From NCERT
NEET - 2013
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Subtopic: Electron Displacement Effects |
82%
From NCERT
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Subtopic: Structural Isomers |
79%
From NCERT
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The curved arrow shows electron movement
1. toward a nucleophile
2. toward an electrophile
3. away from an electrophile
4. in either direction
1. toward a nucleophile
2. toward an electrophile
3. away from an electrophile
4. in either direction
Subtopic: Bond Cleavage & Isomerism |
69%
From NCERT
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The number of \(\sigma\) bonds, \(\pi\) bonds and lone pair of electrons in pyridine respectively are:
1. 12, 2, 1
2. 11, 2, 0
3. 12, 3, 0
4. 11, 3, 1
1. 12, 2, 1
2. 11, 2, 0
3. 12, 3, 0
4. 11, 3, 1
Subtopic: Hybridisation & Structure of Carbon Compounds |
68%
From NCERT
NEET - 2023
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