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Q. No.The plot of ln k vs \({1 \over T}\) for the following reaction
\(2N_2O_5(g) \rightarrow 4NO_2 (g) + O_2(g) \) gives a straight line with the slope of the line equal to \(-1.0 \times 10^4 K \).
The activation energy for the reaction in J mol–1 is:
(Given R = 8.3 J K–1 mol–1)
1.
\(4.0 \times 10^2 \)
2.
\(4.0 \times 10^{-2} \)
3.
\(8.3 \times 10^{-4} \)
4.
\(8.3 \times 10^4 \)
\(2N_2O_5(g) \rightarrow 4NO_2 (g) + O_2(g) \) gives a straight line with the slope of the line equal to \(-1.0 \times 10^4 K \).
The activation energy for the reaction in J mol–1 is:
(Given R = 8.3 J K–1 mol–1)
Subtopic: Arrhenius Equation |
78%
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NEET - 2022
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The half-life of a first-order reaction is 2000 years. If the concentration after 8000 years is 0.02 M, then the initial concentration was:
1. 0.16 M
2. 0.32 M
3. 0.08 M
4. 0.04 M
1. 0.16 M
2. 0.32 M
3. 0.08 M
4. 0.04 M
Subtopic: First Order Reaction Kinetics |
62%
From NCERT
NEET - 2022
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NEET 2025 - Target Batch
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| Statement I: | For complex reactions, order has no meaning. |
| Statement II: | Order of a reaction is experimental quantity. |
| 1. | Statement-I is incorrect but Statement-II is correct |
| 2. | Both Statement-I and Statement-II are correct |
| 3. | Both Statement-I and Statement-II are incorrect |
| 4. | Statement-I is correct but Statement-II is incorrect |
Subtopic: First Order Reaction Kinetics |
61%
From NCERT
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The given graph is a representation of the kinetics of a reaction.
The y and x axes for zero and first-order reactions, respectively are:
The y and x axes for zero and first-order reactions, respectively are:
| 1. | zero order (y=rate and x=concentration), first order (y=rate and x=t1/2) |
| 2. | zero order (y=concentration and x=time), first order (y=t1/2 and x = concentration) |
| 3. | zero order (y=concentration and x= time), first order (y=rate constant and x= concentration) |
| 4. | zero order (y=rate and x=concentration), first order (y=t1/2 and x = concentration) |
Subtopic: Order, Molecularity and Mechanism |
62%
From NCERT
NEET - 2022
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A reaction is 50% complete in 2 hours and 75% complete in 4 hours. The order of the reaction is:
| 1. | 1 | 2. | 2 |
| 3. | 3 | 4. | 0 |
Subtopic: Order, Molecularity and Mechanism |
81%
From NCERT
NEET - 2013
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R):
In the light of the above statements choose the correct answer from the options given below:
| Assertion (A): | A reaction can have zero activation energy. |
| Reason (R): | The minimum extra amount of energy absorbed by reactant molecules so that their energy becomes equal to threshold value, is called activation energy. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Subtopic: Arrhenius Equation |
From NCERT
NEET - 2023
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For a certain reaction, the rate = \(k[A]^2[B],\) when the initial concentration of A is tripled keeping the concentration of B constant, the initial rate would be:
| 1. | Increase by a factor of three |
| 2. | Decrease by a factor of nine |
| 3. | Increase by a factor of six |
| 4. | Increase by a factor of nine |
Subtopic: Order, Molecularity and Mechanism |
79%
From NCERT
NEET - 2023
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The correct options for the rate law that corresponds to overall first order reaction is:
| 1. | \( Rate =k[A]^0[B]^2 \) | 2. | \( Rate =k[A][B] \) |
| 3. | \(Rate=k[A]^{1 / 2}[B]^2 \) | 4. | \(Rate =k[A]^{-1 / 2}[B]^{3 / 2}\) |
Subtopic: Order, Molecularity and Mechanism |
80%
From NCERT
NEET - 2023
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NEET 2025 - Target Batch
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A first-order reaction is carried out at several different temperatures. The data are plotted as In \(k\) vs 1/T.
How is the slope of the graph related to \(E_a\)?
1. \(E_a = \text {slope} \times 8.314 ~J ~mol^{-1} ~K^{-1}\)
2. \(E_a =- \text {slope} \times 8.314 ~J ~mol^{-1} ~K^{-1}\)
3. \(1/E_a = \text {slope} \times 8.314 ~J ~mol^{-1} ~K^{-1}\)
4. \(1/E_a = -\text {slope} \times 8.314 ~J ~mol^{-1} ~K^{-1}\)
How is the slope of the graph related to \(E_a\)?
1. \(E_a = \text {slope} \times 8.314 ~J ~mol^{-1} ~K^{-1}\)
2. \(E_a =- \text {slope} \times 8.314 ~J ~mol^{-1} ~K^{-1}\)
3. \(1/E_a = \text {slope} \times 8.314 ~J ~mol^{-1} ~K^{-1}\)
4. \(1/E_a = -\text {slope} \times 8.314 ~J ~mol^{-1} ~K^{-1}\)
Subtopic: Arrhenius Equation |
85%
From NCERT
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One proposed mechanism for the hydrolysis of ester is shown below.
RCOOR' + H3O+ → RCOHOR'+ + H2O
RCOHOR'+ + H2O → RC(OH)OR'(OH2)+
RC(OH)OR'(OH2)+ + H2O → RCOOH + R'OH + H3O+
An intermediate species among the following is:
RCOOR' + H3O+ → RCOHOR'+ + H2O
RCOHOR'+ + H2O → RC(OH)OR'(OH2)+
RC(OH)OR'(OH2)+ + H2O → RCOOH + R'OH + H3O+
An intermediate species among the following is:
| 1. | RCOHOR'+ | 2. | H3O+ |
| 3. | RCOOR' | 4. | R'OH |
Subtopic: Acid Derivatives - Preparation, Properties & Uses |
85%
From NCERT
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