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The change in the internal energy of an ideal gas does not depend on?

1. Number of moles
2.  Change in temperature
3. Specific heat at constant pressure \(C_p\) of the gas 
4. Specific heat at constant volume \(C_v\) of the gas

Subtopic:  Law of Equipartition of Energy |
 75%
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The translational kinetic energy of \(n\) moles of a diatomic gas at absolute temperature \(T\) is given by:
1. \(\frac{5}{2}nRT\)
2. \(\frac{3}{2}nRT\)
3. \(5nRT\)
4. \(\frac{7}{2}nRT\)

Subtopic:  Kinetic Energy of an Ideal Gas |
 66%
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Which of the following graphs, shows the variation of the mean kinetic energy \(E\) of an ideal gas molecule with temperature \(t ^\circ\text{C}?\)

1. 2.
3. 4.
Subtopic:  Kinetic Energy of an Ideal Gas |
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Two ideal gases have the same number of molecules per unit volume and the radii of their molecules are \(r\) and \(3r\) respectively. The ratio of their mean free path in identical containers will be:
1. \(3:1\) 2. \(9:1\)
3. \(1:1\) 4. \(1:4\)
Subtopic:  Mean Free Path |
 83%
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When a large bubble rises from the bottom of a lake to the surface, its radius doubles. The atmospheric pressure is equal to that of a column of water of height H. The depth of the lake is:

1. H

2. 2H

3. 7H

4. 8H

Subtopic:  Ideal Gas Equation |
 62%
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The figure shows a process for a gas in which pressure (P) and volume (V) of the gas change. If C1 and C2 are the molar heat capacities of the gas during the processes AB and BC respectively, then:

1. C1=C2

2. C1>C2

3. C1<C2

4. C1C2

Subtopic:  Specific Heat |
 66%
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The pressure in a diatomic gas increases from P0 to 3P0, when its volume is increased from V0 to 2V0. The increase in internal energy  will be:
     
1. 6PoV0

2. 8.5PoV0

3. 12.5PoV0

4. 14.5PoV0

Subtopic:  Law of Equipartition of Energy |
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If at a pressure of \(10^6\) dyne/cm2, one gram of nitrogen occupies \(2\times10^4\) c.c. volume, then the average energy of a nitrogen molecule in erg is:

1. \(14\times10^{-13}\) 2. \(10\times10^{-12}\)
3. \(10^{6}\) 4. \(2\times10^{6}\)
Subtopic:  Kinetic Energy of an Ideal Gas |
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Without change in temperature, a gas is forced in a smaller volume. Its pressure increases because its molecules:

1. strike the unit area of the container wall more often.
2. strike the unit area of the container wall at a higher speed.
3. strike the unit area of the container wall with greater force.
4. have more energy.

Subtopic:  Kinetic Energy of an Ideal Gas |
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If the mean free path of atoms is doubled, then the pressure of the gas will become:

1. \(\frac{P}{4}\)                   
2. \(\frac{P}{2}\)
3. \(\frac{P}{8}\)
4. \(P\)

Subtopic:  Mean Free Path |
 72%
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