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Q. No.When the intensity of a light source is increased,
| (a) | the number of photons emitted by the source in unit time increases. |
| (b) | the total energy of the photons emitted per unit time increases. |
| (c) | more energetic photons are emitted. |
| (d) | faster photons are emitted. |
Choose the correct option:
| 1. | (a), (b) | 2. | (b), (c) |
| 3. | (c), (d) | 4. | (a), (d) |
Subtopic: Photoelectric Effect: Experiment |
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The stopping potential \({(V)}\) versus frequency \({(f)}\) of incident radiation is plotted for two photoelectric surfaces \({A}\) and \({B}.\) We can say that the work function of \({A}\):
| 1. | is equal to that of \({B}\) |
| 2. | is greater than that of \({B}\) |
| 3. | is smaller than that of \({B}\) |
| 4. | cannot be related to that of \({B}\) from the graph |
Subtopic: Einstein's Photoelectric Equation |
75%
From NCERT
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Ultraviolet photons, each of energy \(20~\text{eV},\) are incident onto a gas of \(\mathrm {H}\)-atoms, causing the emission of electrons. The kinetic energy of the emitted electrons has the value:
1. \(6.4~\text{eV}\)
2. \(7.2~\text{eV}\)
3. \(3.2~\text{eV}\)
4. \(13.6~\text{eV}\)
1. \(6.4~\text{eV}\)
2. \(7.2~\text{eV}\)
3. \(3.2~\text{eV}\)
4. \(13.6~\text{eV}\)
Subtopic: Electron Emission |
68%
From NCERT
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Given below are two statements:
| Assertion (A): | The photoelectric effect demonstrates the wave nature of light. |
| Reason (R): | The number of photoelectrons emitted is proportional to the frequency of light. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
Subtopic: Particle Nature of Light |
76%
From NCERT
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In the de-Broglie equation, wavelength \(\mathit{\lambda}\) depends upon mass \(m\) and energy \(E\) according to the relation represented as:
1. \(mE^{1/2}\)
2. \(m^{-1/2}E^{1/2}\)
3. \(m^{-1/2}E^{-1/2}\)
4. \(m^{1/2}E^{-1/2}\)
1. \(mE^{1/2}\)
2. \(m^{-1/2}E^{1/2}\)
3. \(m^{-1/2}E^{-1/2}\)
4. \(m^{1/2}E^{-1/2}\)
Subtopic: De-broglie Wavelength |
86%
From NCERT
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Given below are two statements:
| Assertion (A): | The work function of aluminium is \(4.2~\text{eV}\). Emission of electrons will not be possible if two photons, each of energy \(2.5~\text{eV}\), strike an electron of aluminium. |
| Reason (R): | For photoelectric emission, the energy of each photon should be greater than the work function of aluminium. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
Subtopic: Photoelectric Effect: Experiment |
87%
From NCERT
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Light of two different frequencies whose photons have energies \(1~\text{eV}\) and \(2.5~\text{eV}\) respectively, successively illuminate a metal whose work function is \(0.5~\text{eV}\). The ratio of the maximum speeds of the emitted electrons will be:
1. \(1:5\)
2. \(1:4\)
3. \(1:2\)
4. \(1:1\)
1. \(1:5\)
2. \(1:4\)
3. \(1:2\)
4. \(1:1\)
Subtopic: Einstein's Photoelectric Equation |
76%
From NCERT
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Consider a beam of electrons (each electron with energy \(E_0\)) incident on a metal surface kept in an evacuated chamber. Then:
| 1. | no electrons will be emitted as only photons can emit electrons. |
| 2. | electrons can be emitted but all with energy, \(E_0.\) |
| 3. | electrons can be emitted with any energy, with a maximum of \({E}_0-\phi\) (\(\phi\) is the work function). |
| 4. | electrons can be emitted with any energy, with a maximum \(E_0.\) |
Subtopic: Electron Emission |
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Monochromatic light of wavelength \(632.8~\text{nm}\) is produced by a helium-neon laser. The power emitted is \(9.42~\text{mW}\). The energy of each photon in the light beam is:
1. \(4.801 \times 10^{-19}~\text{J}\)
2. \(2.121 \times 10^{-19}~\text{J}\)
3. \(5.043 \times 10^{-19}~\text{J}\)
4. \(3.141 \times 10^{-19}~\text{J}\)
Subtopic: Particle Nature of Light |
62%
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A particle is dropped from a height \(H.\) The de-Broglie wavelength of the particle as a function of height is proportional to:
1. \(H\)
2. \(H^{1/2}\)
3. \(H^{0}\)
4. \(H^{-1/2}\)
Subtopic: De-broglie Wavelength |
66%
From NCERT
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