Calculate the Gibbs energy change when 1 mole of NaCl is dissolved in water at 298 K. Given,
a. Lattice energy of NaCl = 778 kJ mol-1
b. Hydration energy of NaCl =-774.3 kJ mol-1
c. Entropy change at 298 K = 43 JK-1 mol-1
1. | -3.7 kJ | 2. | -9.1 kJ |
3. | -43 kJ | 4. | -13.14 kJ |
The standard enthalpies of the formation of NO2(g) and N2O4(g) are 8 kcal mol–1 and 2 kcal mol–1 respectively. The heat of dimerization of NO2 in the gaseous state is:
1. | 10 k cal mol–1 | 2. | 6.0 k cal mol–1 |
3. | –14 k cal mol–1 | 4. | –6.0 k cal mol–1 |
The average S–F bond energy in kJ mol–1 of SF6 is:
[The values of standard enthalpy of formation of
SF6(g), S(g), and F(g) are –1100, 275, and 80 kJmol–1 respectively.]
1. | 309 kJ mol–1 | 2. | 313 kJ mol–1 |
3. | 305 kJ mol–1 | 4. | 318 kJ mol–1 |