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Out of the two slits of Young’s double-slit experiment, one of the slits is painted to make its intensity less than that of the other slit. Then:
1. the fringes will disappear (uniform illumination).
2. screen will become dark.
3. the contrast between fringes will increase.
4. the contrast between fringes will decrease.

Subtopic:  Young's Double Slit Experiment |
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Two Nicols prisms (polariser and analyser) are oriented in such a way that the maximum amount of light is transmitted. Now, if the analyser is rotated by an angle of \(45^\circ\), what fraction of the maximum intensity of the light will be reduced?
1. \(25\%\)
2. \(75\%\)
3. \(50\%\)
4. \(30\%\)
Subtopic:  Polarization of Light |
 61%
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In Young’s double slit experiment, the two slits are \(0.6\) mm distance apart. The interference pattern is observed on a screen at a distance of \(80\) cm from the slits. The first dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light will be:
1. \(450\) nm
2. \(550\) nm
3. \(650\) nm
4. \(750\) nm
Subtopic:  Superposition Principle |
 79%
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A parallel beam of light of wavelength \(600\) nm falls normally on a slit of width \(a.\) What should the value of \(a\) so that the first-order diffraction minimum occurs at an angle of \(30^\circ\)?
1. \(1.1\times10^{-6}~\text{m}\)
2. \(1.2\times10^{-6}~\text{m}\)
3. \(1.3\times10^{-6}~\text{m}\)
4. \(1.4\times10^{-6}~\text{m}\)
Subtopic:  Diffraction |
 84%
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After passing through a polarizer, a linearly polarized light of intensity \(I\) is incident on an analyser making an angle of \(30^\circ\) with the axes of the polariser. The intensity of light emitted from the analyser will be:
1. \(\dfrac{I}{2}\)

2. \(\dfrac{I}{3}\)

3. \(\dfrac{3I}{4}\)

4. \(\dfrac{2I}{3}\)
Subtopic:  Polarization of Light |
 83%
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The intensities of light coming from two different slits are in the ratio \(1:4\) in Young's double-slit experiment. The ratio of intensities corresponding to the maxima and minima in the interference pattern would be:
1. \(\sqrt2:1\)
2. \(2:1\)
3. \(4:1\)
4. \(9:1\)
Subtopic:  Young's Double Slit Experiment |
 88%
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In a double-slit experiment using light with a wavelength of \(628\) nm, the angular width of a fringe formed on the screen is \(0.1^\circ.\) The separation between the slits is: (use \(\pi=3.14 \))
1. \(3.6\times 10^{-5}~\text{m}\)
2. \(3.6\times 10^{-4}~\text{m}\)
3. \(3.6\times 10^{-5}~\text{cm}\)
4. \(3.6\times 10^{-4}~\text{cm}\)
Subtopic:  Young's Double Slit Experiment |
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In Young's double-slit experiment, slits are separated by \(0.5~\text{mm}\) and the screen is placed \(150~\text{cm}\) away. A beam of light consisting of two wavelengths, \(650~\text{nm}\) and \(975~\text{nm}\) is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both wavelengths coincide is: 
1. \(5.85~\text{mm}\)
2. \(7.8~\text{mm}\)
3. \(4.2~\text{mm}\)
4. \(3.6~\text{mm}\)
Subtopic:  Young's Double Slit Experiment |
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The energy in the phenomenon of interference:
1. is conserved, gets redistributed
2. is equal at every point
3. is not conserved
4. is created in place of bright fringes
Subtopic:  Superposition Principle |
 83%
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Given below are two statements: 
Assertion (A): If the phase difference between the light waves emerging from the slits of Young's experiment is \(\pi\) radian, the central fringe will be dark.
Reason (R): Phase difference is equal to \((2\pi/\lambda)\) times of path difference.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Young's Double Slit Experiment |
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