An AC source given by \(V=V_m\sin(\omega t)\) is connected to a pure inductor \(L\) in a circuit and \(I_m\) is the peak value of the AC current. The instantaneous power supplied to the inductor is:
1. | \(\dfrac{V_mI_m}{2}\mathrm{sin}(2\omega t)\) | 2. | \(-\dfrac{V_mI_m}{2}\mathrm{sin}(2\omega t)\) |
3. | \({V_mI_m}\mathrm{sin}^{2}(\omega t)\) | 4. | \(-{V_mI_m}\mathrm{sin}^{2}(\omega t)\) |
1. | \(800~\Omega\) and \(1.06~\Omega\) | 2. | \(10~\Omega\) and \(500~\Omega\) |
3. | \(800~\Omega\) and \(0.32~\Omega\) | 4. | \(1.06~\Omega\) and \(500~\Omega\) |
Statement I: | In an AC circuit, the current through a capacitor leads the voltage across it. |
Statement II: | \(\pi.\) | In AC circuits containing pure capacitance only, the phase difference between the current and the voltage is
1. | Both Statement I and Statement II are correct. |
2. | Both Statement I and Statement II are incorrect. |
3. | Statement I is correct but Statement II is incorrect. |
4. | Statement I is incorrect but Statement II is correct. |
1. | \(1~\text A\) | 2. | \(1.5~\text{A}\) |
3. | \(2~\text A\) | 4. | \(2.4~\text A\) |
1. | \(1 / \sqrt{2}\) times the rms value of the AC source. |
2. | the value of voltage supplied to the circuit. |
3. | the rms value of the AC source. |
4. | \(\sqrt{2}\) times the rms value of the AC source. |