Q. No.The equivalent capacitance of the circuit between the points \(A~\text{and}~B\) is equal to:
1. \(2C\)
2. \(\dfrac{3C}{2}\)
3. \(3C\)
4. \(\dfrac{5C}{2}\)
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1. \(-MgR\)
2. \(-mgR\)
3. \(\dfrac{-MgR}{\sqrt2}\)
4. \(\dfrac{-mgR}{\sqrt2}\)
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| 1. | \(Q_0V_0\) | 2. | \(\dfrac{Q_0V_0}{2}\) |
| 3. | \(\dfrac{Q_0V_0}{4}\) | 4. | \(-Q_0V_0\) |
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| 1. | \(\dfrac{A_1+A_2}{2}\) | 2. | \(\sqrt{A_1A_2}\) |
| 3. | \(\dfrac{2A_1A_2}{A_1+A_2}\) | 4. | \(\dfrac{A_1^2A_2^2}{A_1+A_2}\) |
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| 1. | \(1\) | 2. | \(2\) |
| 3. | \(4\) | 4. | \(\sqrt2\) |
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The potential difference between \(A\) and \(B\) when \(A\) is connected to \(X\) and \(B\) is connected to \(Y,\) is:
1. \(2.6\) V
2. \(2.4\) V
3. \(6\) V
4. zero
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The potential difference between \(A\) and \(B,\) after \(A\) is connected to \(Y\) and \(B\) to \(X,\) is:
1. \(2.6\) V
2. \(2.4\) V
3. \(6\) V
4. zero
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1. \(10\) V
2. \(5 \sqrt 2\) V
3. \(10 \sqrt 2\) V
4. \(10 (\sqrt {2} -1)\) V
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| 1. | zero | 2. | \(\dfrac{kq }{2R}\) |
| 3. | \(\dfrac{-kq }{ 2R}\) | 4. | \(\dfrac{2kq }{ R}\) |
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| 1. | \(\dfrac{4\pi\varepsilon_0r^2}{d}\) | 2. | \(\dfrac{2\pi\varepsilon_0r^2}{d}\) |
| 3. | \(\dfrac{\pi\varepsilon_0r^2}{d}\) | 4. | \(\dfrac{\pi\varepsilon_0r^2}{2d}\) |
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