The circuit shown in the diagram given below, is set up with all the capacitors initially uncharged.
                     
The potential difference between \(A\) and \(B,\) after \(A\) is connected to \(Y\) and \(B\) to \(X,\) is:
1. \(2.6\) V
2. \(2.4\) V
3. \(6\) V
4. zero

Subtopic:  Capacitance |
 62%
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A charge is uniformly distributed on the circumference of a disc, and the potential at its centre is \(5\) volt. If the charge was uniformly distributed on the surface of this disc, the potential at a point \(P\) on its axis, at a distance equal to the disc's radius from its centre, equals:
1. \(10\) V
2. \(5 \sqrt 2\) V
3. \(10 \sqrt 2\) V
4. \(10 (\sqrt {2} -1)\) V
Subtopic:  Electric Potential |
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A negative point charge \((-q)\) is placed at the centre of a spherical ball of charge distributed uniformly over its volume. The radius of the ball is \(R.\) The electric field on its surface is zero. The potential on its surface is:
1. zero 2. \(\dfrac{kq }{2R}\)
3. \(\dfrac{-kq }{ 2R}\) 4. \(\dfrac{2kq }{ R}\)
Subtopic:  Electric Potential |
 62%
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A capacitance is formed by connecting two metallic balls of radius \(r\) by a conducting wire, and two oppositely charged identical metallic hemispheres \((A,B)\) slightly larger than the balls. The separation between the hemispheres and the respective balls is \(d.\) The capacitance between \(A,B\) is:
1. \(\dfrac{4\pi\varepsilon_0r^2}{d}\) 2. \(\dfrac{2\pi\varepsilon_0r^2}{d}\)
3. \(\dfrac{\pi\varepsilon_0r^2}{d}\) 4. \(\dfrac{\pi\varepsilon_0r^2}{2d}\)
Subtopic:  Capacitance |
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Three capacitors are connected in the configuration shown, with \(C_1=C_3=C\) and \(C_2=2C.\) If a charge \(Q\) is passed through the circuit from \(A\) to \(B\) (with the capacitors initially uncharged), the energies stored in the capacitors, \(C_1,C_2,C_3\) are in the ratio:
1. \(1:2:1\) 2. \(1:\dfrac12:1\)
3. \(1:4:1\) 4. \(1:\dfrac14:1\)
Subtopic:  Energy stored in Capacitor |
 65%
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The potential on the surface of a spherical region varies from \(2\) V to \(4\) V from point to point. There are no charges in the interior of the region.
Assertion (A): The potential at the centre cannot be \(0\) V.
Reason (R): Potential in the interior of a sphere must always be greater than the potential on the surface.
 
1. (A) is True but (R) is False.
2. (A) is False but (R) is True.
3. Both (A) and (R) are True and (R) is the correct explanation of (A).
4. Both (A) and (R) are True but (R) is not the correct explanation of (A).
Subtopic:  Electric Potential |
 63%
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The capacitance of the system (shown in the figure below) of parallel conducting plates, between the two outer plates \((X)\) and the inner plate \((Y)\) is (plate area=\(A,\) plate separation \(d,2d:\) small)
            
1. \(\dfrac{3\varepsilon_0A}{2d}\)

2. \(\dfrac{4\varepsilon_0A}{3d}\)

3. \(\dfrac{\varepsilon_0A}{3d}\)

4. \(\dfrac{\varepsilon_0A}{2d}\)
Subtopic:  Combination of Capacitors |
 72%
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The potential on the surface of a uniform spherical volume charge distribution is \(10~\text{V}\); and it is observed that the potential at its centre is \(15~\text{V}\). If the radius of the sphere is halved, keeping the total charge constant, then the potential at its centre will be:
1. \(15~\text{V}\) 2. \(30~\text{V}\)
3. \(60~\text{V}\) 4. \(120~\text{V}\)
Subtopic:  Electric Potential |
 70%
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Three charges are placed at the three corners of an equilateral triangle as shown in the figure. The potential at the mid-point of a side with opposite charges is \(2~\text V.\) The potential at the centre of the triangle is:
1. \(2~\text V\) 2. \(3~\text V\)
3. \(2\sqrt3~\text V\) 4. \(\dfrac{2}{\sqrt3}~\text V\)
Subtopic:  Electric Potential |
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The capacitance of the system of capacitors connected in the circuit, between \(A\) and \(B,\) equals:
                
1. \(4~\mu\)F 2. \(2.5~\mu \)F
3. \(2.4~\mu \)F 4. \(1.5~\mu \)F
Subtopic:  Combination of Capacitors |
 67%
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