Q. No.Consider the circuit shown in the figure given below. The input voltage is ViVi, the current through the diode is IzIz, and the current through the load is ILIL.
1.
If Vi=15 V and RL=40 Ω, and Iz=0.375 AIf Vi=15 V and RL=40 Ω, and Iz=0.375 A
2.
If Vi=10 V and RL=5 Ω, and IL=1 AIf Vi=10 V and RL=5 Ω, and IL=1 A
3.
If Vi=20 V and RL=20 Ω, and Iz=0.25 AIf Vi=20 V and RL=20 Ω, and Iz=0.25 A
4.
If Vi=20 V and RL=10 Ω, and Iz=0.5 AIf Vi=20 V and RL=10 Ω, and Iz=0.5 A
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Consider the following two statements and mark the correct option.
| (I) | If Vi>2 V, then Vo=ViIf Vi>2 V, then Vo=Vi |
| (II) | If Vi<2 V, then Vo=2 VIf Vi<2 V, then Vo=2 V |
| 1. | (I) is True. |
| 2. | (II) is True. |
| 3. | (I) and (II) are both True. |
| 4. | (I) and (II) are both False. |
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| Assertion (A): | The resistance of a photodiode decreases when light having photons of sufficient energy is incident on it. |
| Reason (R): | When energetic photons fall on the p-np-n junction of a photodiode, electron-hole pairs are created due to the breaking of the valence bonds. |
| 1. | (A) is True but (R) is False. |
| 2. | (A) is False but (R) is True. |
| 3. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 4. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
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| 1. | 30√2 V30√2 V | 2. | 15 V15 V |
| 3. | 15√2 V15√2 V | 4. | 10 V10 V |
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The current through the circuit is:
1. 4040 mA
2. 5454 mA
3. 3333 mA
4. 2626 mA
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1. If VAB>0,VAX>0
2. If VAB>0,VXY>0
3. If VAB<0,VXY>0
4. If VAB<0,VAX>0
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| A | B | C | Y (Output) |
| 1 | X | 1 | 1 |
| 0 | 1 | X | 1 |
| All other cases | 0 | ||
| 1. |  |
| 2. |  |
| 3. |  |
| 4. |  |
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Here, T= absolute temperature, V= voltage across the diode, k= Boltzmann's constant and i0= the drift current.
Then, the differential resistance of the diode (dVdi) is given by:
1. (constant)i
2. (constant)i2
3. constanti
4. (constant)e−βi, β-constant
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| 1. |  |
| 2. |  |
| 3. |  |
| 4. |  |
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This diode is connected with a resistance of 5 Ω in series with it as shown below:
Which of the following shows the dependence of the voltage VAB and the current i, when the diode is forward-biased?
(VAB in volt, i in ampere)
| 1. | VAB=i⋅5+0.6 |
| 2. | VAB=i⋅5−0.6 |
| 3. | VAB=i⋅5+(0.6−5) |
| 4. | VAB=i⋅5+(0.6+5) |
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