- 1(current)
Q. No.| 1. | \(1:2\) | 2. | \(1:1\) |
| 3. | \(\sqrt{2}:1\) | 4. | \(1:\sqrt{2}\) |
1. \(1\%\)
2. \(2\%\)
3. \(3\%\)
4. \(4\%\)
A uniform rope, of length \(L\) and mass \(m_1,\) hangs vertically from a rigid support. A block of mass \(m_2\) is attached to the free end of the rope. A transverse pulse of wavelength \(\lambda_1\) is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is \(\lambda_2.\) The ratio \(\frac{\lambda_2}{\lambda_1}\) is:
| 1. | \(\sqrt{\dfrac{m_1+m_2}{m_2}}\) | 2. | \(\sqrt{\dfrac{m_2}{m_1}}\) |
| 3. | \(\sqrt{\dfrac{m_1+m_2}{m_1}}\) | 4. | \(\sqrt{\dfrac{m_1}{m_2}}\) |
A steel wire has a length of \(12.0~\text m\) and a mass of \(2.10~\text{kg}.\) What should be the tension in the wire so that the speed of a transverse wave on the wire equals the speed of sound in dry air, at \(20^{\circ}\text{C}\) (which is \(343~\text{m/s}\) )?
1. \(4.3\times10^3~\text{N}\)
2. \(3.2\times10^4~\text{N}\)
3. \(2.06\times10^4~\text{N}\)
4. \(1.2\times10^4~\text{N}\)
\(y=(0.02~\text{m})\sin\left[{{2}\pi \left({\frac{t}{{0.04}~(\text{s})}-\frac{x}{{0.50}~(\text{m})}}\right)}\right].\) The tension in the string will be:
| 1. | \(4.0~\text{N}\) | 2. | \(12.5~\text{N}\) |
| 3. | \(0.5~\text{N}\) | 4. | \(6.25~\text{N}\) |
(take \(g=9.8~\text{m/s}^2\) )
1. \(1~\text s\)
2. \(1.4~\text s\)
3. \(2~\text s\)
4. \(1.9~\text s\)
The speed of the pulse is:
| 1. | maximum at \(A,\) minimum at \(O\) |
| 2. | minimum at \(A,\) maximum at \(O\) |
| 3. | uniform |
| 4. | minimum at \(A\) and \(O,\) maximum in the middle |
- 1(current)
Q. No.
© 2025 GoodEd Technologies Pvt. Ltd.