Q. No.| 1. | \(\frac{4F}{3}\) | 2. | \(F\) |
| 3. | \(\frac{9F}{16}\) | 4. | \(\frac{16F}{9}\) |
The ratio of the electric flux linked with shell \(A\) and shell \(B\) in the diagram shown below is:
| 1. | \(1: 1\) | 2. | \(1: 2\) |
| 3. | \(1: 4\) | 4. | \(4: 2\) |
The magnitude of electric field intensity at a distance \({R}~(R \gg L )\) varies as:
| 1. | \(\dfrac{1}{{R}^{6}}\) | 2. | \(\dfrac{1}{{R}^{2}}\) |
| 3. | \(\dfrac{1}{{R}^{3}}\) | 4. | \(\dfrac{1}{{R}^{4}}\) |
A square surface of a side \(L\) \(\text{(m)}\) is in the plane of the paper. A uniform electric field \(\vec{E}\) \(\text{(V/m)},\) also in the plane of the paper, is limited only to the lower half of the square surface, (see figure). The electric flux in SI units associated with the surface is:
| 1. | \(EL^2/ ( 2ε_0 )\) | 2. | \(EL^2 / 2\) |
| 3. | zero | 4. | \(EL^2\) |
| 1. | \(2~\text{mC}\) | 2. | \(8~\text{mC}\) |
| 3. | \(6~\text{mC}\) | 4. | \(4~\text{mC}\) |
(Given that the charge of the proton and electron each \(=1.6\times 10^{-19},\) the mass of the electron \(=9.11\times 10^{-31}~\text{kg},\) the mass of the proton \(=1.67\times 10^{-27}~\text{kg}\) ):
1. \(10^{20}\)
2. \(10^{30}\)
3. \(10^{40}\)
4. \(10\)
Two parallel infinite line charges with linear charge densities \(+\lambda~\text{C/m}\) and \(+\lambda~\text{C/m}\) are placed at a distance \({R}.\) The electric field mid-way between the two line charges is:
| 1. | \(\frac{\lambda}{2 \pi \varepsilon_0 {R}}~\text{N/C}\) | 2. | zero |
| 3. | \(\frac{2\lambda}{ \pi \varepsilon_0 {R}} ~\text{N/C}\) | 4. | \(\frac{\lambda}{ \pi \varepsilon_0 {R}}~\text{N/C}\) |
A dipole is placed in an electric field as shown. In which direction will it move?
| 1. | towards the left as its potential energy will decrease. |
| 2. | towards the right as its potential energy will increase. |
| 3. | towards the left as its potential energy will increase. |
| 4. | towards the right as its potential energy will decrease. |
The acceleration of an electron due to the mutual attraction between the electron and a proton when they are \(1.6~\mathring{A}\) apart is:
\(\left(\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9~ \text{Nm}^2 \text{C}^{-2}\right)\)
| 1. | \( 10^{24} ~\text{m/s}^2\) | 2 | \( 10^{23} ~\text{m/s}^2\) |
| 3. | \( 10^{22}~\text{m/s}^2\) | 4. | \( 10^{25} ~\text{m/s}^2\) |
The electric field in a certain region is acting radially outward and is given by \(E=Aa.\) A charge contained in a sphere of radius \(a\) centered at the origin of the field will be given by:
| 1. | \(4 \pi \varepsilon_{{o}} {A}{a}^2\) | 2. | \(\varepsilon_{{o}} {A} {a}^2\) |
| 3. | \(4 \pi \varepsilon_{{o}} {A} {a}^3\) | 4. | \(\varepsilon_{{o}} {A}{a}^3\) |
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