The figure shows a rod of length \(5\) m. Its ends, \(A\) and \(B\), are restrained to moving in horizontal and vertical guides. When the end \(A\) is \(3\) m above \(O\), it moves at \(4\) m/s. The velocity of end \(B\) at that instant is:
                         
1. \(2\) m/s

2. \(3\) m/s

3. \(4\) m/s

4. \(0.20\) m/s

Subtopic:  String Constraint |
 69%
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In the given figure, the spring balance is massless, so the reading of the spring balance will be:
                       

1. \(2\) kg 2. \(3.5\) kg
3. \(2.9\) kg 4. \(3.1\) kg
Subtopic:  Application of Laws |
 75%
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A small coin is kept at a distance \(r\) from the centre of a gramophone disc rotating at an angular speed \(\omega\). The minimum coefficient of friction for which a coin will not slip is:
1. \(\dfrac{rω^{2}}{g}\)
2. \(\dfrac{g}{r\omega^2}\)
3. \(\dfrac{r^2ω^{2}}{g}\)
4. \(\dfrac{rω}{g}\)

Subtopic:  Uniform Circular Motion |
 83%
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A block of mass \(2\) kg is placed on inclined rough surface \(AC\) (as shown in the figure) of coefficient of friction \(\mu.\) If \(g=10\) ms–1, the net force (in N) on the block will be:
                    
1. \(10\sqrt3\)
2. zero
3. \(10\)
4. \(20\)
Subtopic:  Friction |
 67%
From NCERT
NEET - 2023
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The distance covered by a body of mass \(5\) g having linear momentum \(0.3\) kg-m/s in \(5\) s is:
1. \(300\) m
2. \(30\) m
3. \(3\) m
4. \(0.3\) m
Subtopic:  Newton's Laws |
 71%
From NCERT
NEET - 2022
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Calculate the maximum acceleration of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is \(0.15\). (take \(g=10\) ms–2)
1. \(50\) ms–2 2. \(1.2\) ms–2
3. \(150\) ms–2 4. \(1.5\) ms–2
Subtopic:  Friction |
 82%
From NCERT
NEET - 2023
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A point mass \(m\) is moved in a vertical circle of radius \(r\) with the help of a string. The velocity of the mass is \(\sqrt{7 g r} \) at the lowest point. The tension in the string at the lowest point will be: 
1. \(6mg\)
2. \(7mg\)
3. \(8mg\)
4. \(mg\)

Subtopic:  Non Uniform Vertical Circular Motion |
 76%
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A body of mass \(m\) is kept on a rough horizontal surface (coefficient of friction = \(\mu).\) A horizontal force is applied to the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by \(\vec {F}\) where:
1. \(|{\vec {F}}| = mg+\mu mg\)
2. \(|\vec {F}| =\mu mg\)
3. \(|\vec {F}| \le mg\sqrt{1+\mu^2}\)
4. \(|\vec{F}| = mg\)

Subtopic:  Friction |
 75%
From NCERT
NEET - 2019
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On the application of an impulsive force, a sphere of mass \(500\) grams starts moving with an acceleration of \(10\) m/s2. The force acts on it for \(0.5\) s. The gain in the momentum of the sphere will be:
1. \(2.5\) kg-m/s

2. \(5\) kg-m/s

3. \(0.05\) kg-m/s

4. \(25\) kg-m/s

Subtopic:  Newton's Laws |
 83%
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In the diagram shown, the normal reaction force between \(2\) kg and \(1\) kg blocks is:
(Consider the surface to be smooth and \(g=10\) ms–2 )

            
1. \(25\) N
2. \(39\) N
3. \(6\) N
4. \(10\) N
Subtopic:  Tension & Normal Reaction |
 54%
From NCERT
NEET - 2022
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