A galvanometer $G$ (having very small resistance), when connected with a resistance of $10~\text k\Omega$ in series, can function as a voltmeter measuring a maximum voltage of $20$ V. The current required to give a full scale deflection on the galvanometer is:
1. $0.1$ mA
2.   $0.2$ mA
3.   $1$ mA
4.   $2$ mA

Subtopic: Moving Coil Galvanometer |

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Q35:

A conducting wire is bent into the form of a square

A B C D,

$ABCD,$ and electrical connections are established in two different ways:

(I)	at two adjacent vertices $A,B$
(II)	at two points $A,C$ at the ends of a diagonal.

The same potential difference is established between the two connected ends. Current is, however, allowed to take only a single path from the positive to the negative terminal by disconnecting the other path. Let the magnetic field at the centre in these cases be

B_{I}, B_{II} .

$B_\text I,B_\text{II}.$ Then,

\frac{B_{I}}{B_{II}} =

$\frac{B_\text I}{B_\text{II}}=$

1.	$2$	2.	$\dfrac12$
3.	$\dfrac{1}{\sqrt2}$	4.	$1$

Subtopic: Magnetic Field due to various cases |

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Q36:

A charged particle of charge

q,

$q,$ mass

m

$m$ moves in a circular path in a uniform magnetic field

B .

$B.$ The current due to the motion of this particle has the average value:

1.	$\dfrac{q^2B}{2\pi m}$	2.	$\dfrac{qB^2}{m}$
3.	$\dfrac{2\pi m}{q^2B}$	4.	$\dfrac{qB}{m^2}$

Subtopic: Lorentz Force |

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Q37:

Two long parallel wires carrying currents

I_{1}

$I_1$ and

I_{2}

$I_2$ give a magnetic field of

3

$3$ G at a point exactly mid-way between the two wires. When one of the currents is reversed, the field becomes

5

$5$ G. The ratio of the large current to the smaller one is:

1.	$2$	2.	$\dfrac43$
3.	$\dfrac32$	4.	$4$

Subtopic: Magnetic Field due to various cases |

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Q38:

Given below are two statements:

Statement I:	A charged particle moving in a magnetic field experiences a force which is zero only when it moves in the direction of the field or against it.
Statement II:	Whenever a charged particle moves in a uniform magnetic field, its trajectory may be a circle, a straight line or a helix.

1.	Statement I is incorrect and Statement II is correct.
2.	Both Statement I and Statement II are correct.
3.	Both Statement I and Statement II are incorrect.
4.	Statement I is correct and Statement II is incorrect.

Subtopic: Lorentz Force |

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Q39:

A current

I,

$I,$ flowing through a long straight wire produces a magnetic field of

4 \times 10^{- 3}

$4\times10^{-3}$ T at a point

P

$P$ ,

20

$20$ cm away. If the wire is replaced by a circular wire of radius

20

$20$ cm, centred at

P

$P$ and carrying the same current

I,

$I,$ then the magnetic field at

P

$P$ will be:

1.	$4\pi\times10^{-3}$ T
2.	$\dfrac4\pi\times10^{-3}$ T
3.	$4\times10^{-3}$ T
4.	$2\times10^{-3}$ T

Subtopic: Magnetic Field due to various cases |

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Q40:

Given below are two statements:

Statement I:	If a galvanometer is connected with a high resistance in series with it, it can be used as an ammeter.
Statement II:	If a galvanometer is connected with a low resistance in parallel with it, it can be used as a voltmeter.

1.	Statement I is incorrect and Statement II is correct.
2.	Both Statement I and Statement II are correct.
3.	Both Statement I and Statement II are incorrect.
4.	Statement I is correct and Statement II is incorrect.

Subtopic: Moving Coil Galvanometer |

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Q33:

A charged particle (charge:

q

$q$ ) moves in a circular orbit in a uniform magnetic field, its orbit enclosing a magnetic flux

Φ .

$\Phi.$ The angular momentum of the particle is:

1.	$q\Phi$	2.	$\dfrac{q\Phi}{2\pi}$
3.	$\pi q\Phi$	4.	$\dfrac{q\Phi}{\pi}$

Subtopic: Lorentz Force |

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Q32:

An ammeter having a resistance of

0.1 Ω

$0.1~ \Omega$ can measure a maximum current of

2 A

$2~\text{A}$ . To convert it into a voltmeter that can measure upto

50 V,

$50~\text{V},$ one must add:

1.	a resistance of $25~\Omega$ in series
2.	a resistance of $\dfrac1{25}~\Omega$ in series
3.	a resistance of $25~\Omega$ in parallel
4.	a resistance of $\dfrac1{25}~\Omega$ in parallel

Subtopic: Conversion to Ammeter & Voltmeter |

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Q31:

A long straight current-carrying wire is placed along the axis of a solenoid and it is found that the field within the solenoid at a distance of

\frac{r}{10}

$\dfrac r{10}$ from the wire is doubled when a current

I

$I$ passes through the wire and the solenoid,

r

$r$ being the radius of the solenoid. The number of turns per unit length of the solenoid are:

1.	$\dfrac{5}{\sqrt3r}$	2.	$\dfrac{5}{\sqrt3\pi r}$
3.	$\dfrac{5}{r}$	4.	$\dfrac{5}{\pi r}$

Subtopic: Magnetic Field due to various cases |

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