All the resistances in circuit are $2~\Omega$ each, $E_1=4~\text{V}$ and $E_2=1~\text{V}$ . The potential difference between $C$ and $D$ (i.e. $V_{C}-V_{D}$ ) is:

1. $1.5~\text{V}$ 2. $-1.5~\text{V}$

3. $1.2~\text{V}$ 4. $-1.2~\text{V}$

Subtopic: Kirchoff's Voltage Law |

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Q19:

A cell is connected between

A

$A$ and

B

$B$ and it is observed that

V_{C} = V_{D}

$V_{C}=V_{D}$ while the corresponding ammeter current is also noted. When the cell (between

A

$A$ and

B

$B$ ) is disconnected, and ends

B

$B$ and

C

$C$ are connected: the current through an ammeter

A

$A$ is found to have the same magnitude (but in opposite direction). Then, the resistance

R

$R$ is:

1.	equals $400~\Omega.$
2.	equals $200~\Omega.$
3.	can have any value less than $400~\Omega.$
4.	cannot be determined from the given information.

Subtopic: Kirchoff's Voltage Law |

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Q20:

All the cells, shown in the figure below, are of

2 V,

$2~\text V,$ and all the resistances are

1 Ω .

$1~\Omega.$ When a potential difference

V

$V$ is applied between

A

$A$ and

B,

$B,$ the current through the circuit doubles compared to the situation when the potential difference is made zero. Then;

1.	$V=2$ volts, positive at $A.$
2.	$V=2$ volts, negative at $A.$
3.	$V=6$ volts, positive at $A.$
4.	$V=6$ volts, negative at $A.$

Subtopic: Kirchoff's Voltage Law |

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Q21:

All the resistances in the circuit shown below are

2 Ω .

$2~\Omega.$ The equivalent resistance between

A

$A$ and

C

$C$ is:

1.	$4~\Omega$	2.	$2~\Omega$
3.	$\dfrac43~\Omega$	4.	$\dfrac{10}3~\Omega$

Subtopic: Combination of Resistors |

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Q22:

The potential difference

V_{A B}

$V_{AB}$ (in volts) is plotted as a function of the resistance

R .

$R.$ The graph is given by:

1.		2.
3.		4.

Subtopic: Derivation of Ohm's Law |

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Q23:

The current flowing through the left

20 Ω

$20~\Omega$ resistor is:

1.	$1~\text A$	2.	$0.5~\text A$
3.	$2.5~\text A$	4.	$3~\text A$

Subtopic: Kirchoff's Voltage Law |

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Q24:

A

20 V

$20~\text V$ cell delivers the same power to a

2 Ω

$2~\Omega$ resistor as it does to an

8 Ω

$8~\Omega$ resistor. The internal resistance of the cell is:
1.

2 Ω

$2~\Omega$
2.

4 Ω

$4~\Omega$
3.

6 Ω

$6~\Omega$
4.

1.6 Ω

$1.6~\Omega$

Subtopic: Heating Effects of Current |

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Q25:

Two cells having emfs

3

$3$ V and

2

$2$ V are connected in parallel and they give an emf of

0.5

$0.5$ V in the same sense as

3

$3$ V

-

$-$ cell. The internal resistances of the cells are

r_{1}

$r_1$ and

r_{2}

$r_2$ respectively. If one cell is reversed, their combined emf becomes

2.5

$2.5$ V. The ratio of their internal resistances

(\frac{r_{1}}{r_{2}})

$\Big(\dfrac{r_1}{r_2}\Big)$ is:
1.

1

$1$
2.

\frac{1}{2}

$\dfrac12$
3.

\frac{2}{1}

$\dfrac21$
4.

\sqrt{2}

$\sqrt2$

Subtopic: Grouping of Cells |

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Q26:

In the Wheatstone Bridge arrangement shown, the resistance

P

$P$ is

2 Ω .

$2~ \Omega.$ The bridge is initially balanced. If P and Q are interchanged: an amount equal to

S

$S$ has to be added to

R

$R$ to restore the balance. The resistance

Q

$Q$ equals (nearly):

1.

2 Ω

$2 ~\Omega$
2.

3.2 Ω

$3.2 ~\Omega$
3.

4 Ω

$4 ~\Omega$
4.

6.4 Ω

$6.4 ~\Omega$

Subtopic: Wheatstone Bridge |

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Q27:

Current density is the current crossing per unit area. Consider a cylindrical wire of uniform cross-section

A,

$A,$ carrying a current

I .

$I.$ Imagine a cross-section formed by a "

30^{\circ}

$30^\circ$ -cut" as shown (the wire is not really cut). The current density perpendicular to this cross-section is:

1.	$\dfrac{I}{A}$	2.	$\dfrac{I}{A}~\cos30^\circ$
3.	$\dfrac{2I}{A}$	4.	$\dfrac{I}{A}~\sin30^\circ$

Subtopic: Current & Current Density |

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All the resistances in circuit are $2~\Omega$ each, $E_1=4~\text{V}$ and $E_2=1~\text{V}$ . The potential difference between $C$ and $D$ (i.e. $V_{C}-V_{D}$ ) is:

1. $1.5~\text{V}$ 2. $-1.5~\text{V}$

3. $1.2~\text{V}$ 4. $-1.2~\text{V}$

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1.	$1.5~\text{V}$	2.	$-1.5~\text{V}$
3.	$1.2~\text{V}$	4.	$-1.2~\text{V}$

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