Q. No.A transformer has \(100\) turns in its primary. It has two secondary circuits: one with \(10\) turns and the other with \(20\) turns. The RMS voltage across the primary is \(30~\text{V}.\) The secondaries are connected to \(10~\Omega\) loads, as shown. Assuming no power loss, the RMS current in the primary is:
1. \(0.2~\text{A}\)
2. \(0.15~\text{A}\)
3. \(0.45~\text{A}\)
4. \(0.9~\text{A}\)
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| 1. | \(f_o = \dfrac{10^3 + 10^5}{2}\) Hz |
| 2. | \(f_o > \dfrac{10^3 + 10^5}{2}\) Hz |
| 3. | \(f_o < \dfrac{10^3 + 10^5}{2}\) Hz |
| 4. | \(f_o = {10^3 + 10^5}\) Hz |
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| 1. | \(R_L = 100\sqrt 2~\Omega\) | 2. | \(R_L = \dfrac{100}{\sqrt 2}~\Omega \) |
| 3. | \(R_L = 100~\Omega\) | 4. | \(R_L = 200~\Omega\) |
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Then:
| 1. | \(\dfrac{L}{C}=R^2 \) | 2. | \(\dfrac{L}{C}=2R^2\) |
| 3. | \(\dfrac{L}{C}=3R^2\) | 4. | \(\dfrac{L}{C}=\dfrac13R^2\) |
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| (A) |  |
| (B) |  |
| (C) |  |
2. A, B
3. A, B, C
4. None of the above
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1. \(V_o = V_m\)
2. \(V_o < V_m \)
3. \(V_o > V_m\)
4. any of the above can be possible.
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In the given scenario, the voltage, \(V_2 > V_1,\) and no current flow through the source on the left. The phase difference between the two sources is \(\phi.\)
Which of the following expressions correctly relates \(\phi\text{?}\)
| 1. | \(R\sin\phi= \dfrac{1}{\omega C}\) | 2. | \(R\cos\phi= \dfrac{1}{\omega C}\) |
| 3. | \(R\tan\phi= \dfrac{1}{\omega C}\) | 4. | \(R\cot\phi= \dfrac{1}{\omega C}\) |
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| 1. | \(\dfrac{V_r}{3}\) | 2. | \(\dfrac{2V_r}{3}\) |
| 3. | \(\dfrac{V_r}{2}\) | 4. | \(V_r\) |
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| 1. | zero | 2. | \(\sqrt 2 V_r \) |
| 3. | \(2 V_r\) | 4. | \(\dfrac{V_r}{\sqrt 2}\) |
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1. \(0.4~\text{A}\)
2. \(0.8~\text{A}\)
3. \(6.4~\text{A}\)
4. \(12.8~\text{A}\)
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