Q. No.| 1. | \(\frac{h}{\sqrt{m k T}}\) | 2. | \(\frac{h}{\sqrt{3 m k T}}\) |
| 3. | \(\frac{2 h}{\sqrt{3 m k T}}\) | 4. | \(\frac{2 h}{\sqrt{m k T}}\) |
1. \(6\lambda\)
2. \(4\lambda\)
3. \(\dfrac{\lambda}{4}\)
4. \(\dfrac{\lambda}{6}\)
1. \(0.31~\mathring{A}\)
2. \(0.41~\mathring{A}\)
3. \(0.5~\mathring{A}\)
4. \(0.16~\mathring{A}\)
When a metallic surface is illuminated with radiation of wavelength , the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2, the stopping potential is .The threshold wavelength for metallic surface is:
1. 5
2.
3. 3
4. 4
If V be the accelerating voltage, then the maximum frequency of continuous x-rays is given by
1.
2.
3.
4.
A radiation of energy 'E' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (c=velocity of light)
1. E/c
2. 2E/c
3. 2E/c2
4. E/c2
An electron of mass m and a photon have the same energy E. Find the ratio of de-Broglie wavelength associated with the electron to that associated with the photon. (c is the velocity of light)
1. \(+3\) V
2. \(+4\) V
3. \(-1\) V
4. \(-3\) V
The maximum kinetic energy of photoelectron emitted from the surface of work function f due to incidence of light of frequency n is E. If the frequency of incident light is doubled, then maximum kinetic of emitted photon will be
1. 2E
2. 2E - f
3. 2E + f
4. 2E + 2f
1. \(\lambda_0 = \frac{2mc\lambda^2}{h}\)
2. \(\lambda_0 = \frac{2h}{mc}\)
3. \(\lambda_0 = \frac{2m^2c^2\lambda^3}{h^2}\)
4. \(\lambda_0 = \lambda\)
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