1. | \(13.6~\text{eV}\) |
2. | \(\dfrac{13.6} {2}~\text{eV}\) |
3. | \(13.6×\left(\dfrac{3}{4}\right)~\text{eV}\) |
4. | \(13.6×\left(\dfrac14-\dfrac19\right)~\text{eV}\) |
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Assertion (A): | When light consisting of wavelengths corresponding to the Balmer series is incident on a gas containing \(\mathrm{He}^{+}\) ions in the first three excited states - it can be absorbed by the \(\mathrm{He}^{+}\) ions. |
Reason (R): | All the energy levels of the \(\mathrm{He}^{+}\) ions are the same as those of the \(\mathrm{H}\) atoms. |
1. | (A) is True but (R) is False. |
2. | (A) is False but (R) is True. |
3. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
4. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
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1. | the same phase. |
2. | the same energy. |
3. | the same direction. |
4. | the same phase, energy, and direction. |
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1. | 2 possible energy values. |
2. | 3 possible energy values. |
3. | 4 possible energy values. |
4. | 5 possible energy values. |
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1. | \(\dfrac{6}{5}\) | 2. | \(\dfrac{5}{6}\) |
3. | \(\dfrac{27}{32}\) | 4. | \(\dfrac{32}{27}\) |
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1. | be emitted with excess kinetic energy |
2. | be excited to a higher state, but not emitted |
3. | be excited to a higher state and then return to the ground state |
4. | remain in the ground state |
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Assertion (A): | The energy of the photon causing the \(n=2\rightarrow4\) transition in the \(\mathrm{He}^+\text-\)ion is equal to the one causing the \(n=1\rightarrow2\) transition in the \(\mathrm{H}\text-\)atom. |
Reason (R): | The energy level corresponding to the \(n^{\text{th}}\) quantum number of the \(\mathrm{H}\text-\)atom has the same value as the \(2n^{\text{th}}\) level of the \(\mathrm{He}^{+}\text-\)ion. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | (A) is False but (R) is True. |
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1. | \(\dfrac{13.6}{n^4}\) eV | 2. | \(\dfrac{6.8}{n^3}\) eV |
3. | \(\dfrac{27.2}{n^3}\) eV | 4. | \(\dfrac{54.4}{n^2}\) eV |
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