1. | \(20~\Omega\) | 2. | \(4.8~\Omega\) |
3. | \(10~\Omega\) | 4. | \(5~\Omega\) |
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1. | \(3\) | 2. | \(4\) |
3. | \(\dfrac13\) | 4. | \(1\) |
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Assertion (A): | The fractional error in \(R\) is most affected by that of the smallest resistance in the combination, other things being equal. |
Reason (R): | In parallel, the conductances add. The contribution to the overall error in the conductance is largest for the largest conductance or the smallest resistance. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | (A) is False but (R) is True. |
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1. | \(3R\) | 2. | \(\Large\frac{5R}{2}\) |
3. | \(\Large\frac{4R}{3}\) | 4. | \(\Large\frac{3R}{2}\) |
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1. | \(18~\Omega\) | 2. | \(9~\Omega\) |
3. | \(4.5~\Omega\) | 4. | \(2.25~\Omega\) |
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1. | \(4~\Omega\) | 2. | \(2~\Omega\) |
3. | \(\dfrac43~\Omega\) | 4. | \(\dfrac{10}3~\Omega\) |
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Statement I: | The voltage across each resistor is \(60~\text V.\) |
Statement II: | The current through each resistor is \(6~\text A.\) |
1. | Statement I is incorrect and Statement II is correct. |
2. | Both Statement I and Statement II are correct. |
3. | Both Statement I and Statement II are incorrect. |
4. | Statement I is correct and Statement II is incorrect. |
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1. | \(20~\Omega\) | 2. | \(4.8~\Omega\) |
3. | \(10~\Omega\) | 4. | \(5~\Omega\) |
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Identical resistances, of value \(R\), each, are connected along the edges of a tetrahedron. If the equivalent resistance of this combination is measured between two vertices, it will be:
1. | \(\dfrac{R}{2}\) | 2. | \(\dfrac{R}{4}\) |
3. | \(\dfrac{R}{6}\) | 4. | \(2R\) |
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