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Q. No.
A wave pulse travels along a taut string towards a fixed end as shown in the adjacent figures:
           
The reflected pulse is correctly shown by:
1. 2.
3. 4.
Subtopic:  Wave Motion |
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Sinusoidal sound waves of the same frequency travelling in air along the \(x\)-axis and the \(y\)-axis arrive in phase with each other at the origin. Their amplitudes are equal to \(A\) (each). The amplitude of the vibration at the origin is:
               
1. \(A\)
2. \(\sqrt 2A\)
3. \(2A\)
4. \((2+\sqrt2)A\)
Subtopic:  Wave Motion |
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A waveform given by:    \(y=3A\sin(\omega t-kx)\)
is superposed with another waveform \(y=4A\cos(\omega t-kx).\) The amplitude of the resulting waveform will be:
1. \(7A\) 2. \(A\)
3. \(3.5A\) 4. \(5A\)
Subtopic:  Wave Motion |
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A tuning fork, placed in a room, vibrates according to the equation:    \(Y=(10^{-4}~\text m)\sin\Big({\large\frac{2\pi t}{0.01~\text s}}\Big) \) where \(Y\) is the displacement of the tip of a prong. The speed of sound in air is \(330~\text{m/s.}\) The amplitude of vibration of the prong is:
1. \(10^{-4}~\text{m}\)
2. \(2\times10^{-4}~\text{m}\)
3. \(10^{-6}~\text{m}\)
4. \(2\times10^{-6}~\text{m}\)
Subtopic:  Wave Motion |
 85%
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A tuning fork, placed in a room, vibrates according to the equation:    \(Y=(10^{-4}~\text m)\sin\left({\Large\frac{2\pi t}{0.01~\text s}}\right)\) where \(Y\) is the displacement of the tip of a prong. The speed of sound in air is \(330~\text{m/s.}\) The frequency of the tuning fork is:
1. \(100~\text{Hz}\)
2. \(50~\text{Hz}\)
3. \(200~\text{Hz}\)
4. \(200\pi~\text{Hz}\)
Subtopic:  Wave Motion |
 86%
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