- 1(current)
Q. No.
| 1. | \(\sqrt{\dfrac{4L\sin\theta}{g}} \) | 2. | \(\sqrt{\dfrac{8L\sin\theta}{g}} \) |
| 3. | \(\sqrt{\dfrac{8L}{g\sin\theta}} \) | 4. | \(\sqrt{\dfrac{4L}{g\sin\theta}} \) |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
A particle moves in the x-y plane according to the equation
\(x = A \cos^2 \omega t\) and \(y = A \sin^2 \omega t\)
Then, the particle undergoes:
| 1. | uniform motion along the line \(x + y = A\) |
| 2. | uniform circular motion along \(x^2 + y^2 = A^2\) |
| 3. | SHM along the line \(x + y = A\) |
| 4. | SHM along the circle \(x^2 + y^2 = A^2\) |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
The equation of motion of a particle that starts moving at \(t=0\) s is given by \({x}=5 \sin \left(\dfrac{\pi t}{2}+\dfrac{\pi}{3}\right) \) where \(x\) is in cm and time \(t\) is in second. The time, when the particle first comes to rest, is:
| 1. | \(\dfrac{1}{3}\) s | 2. | \(\dfrac{7}{6}\) s |
| 3. | \(\dfrac{2}{3}\) s | 4. | \(\dfrac{13}{6}\) s |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
- 1(current)
Q. No.
© 2025 GoodEd Technologies Pvt. Ltd.