- 1(current)
Q. No.A block of mass \(1\) kg is suspended by means of a spring, and the system is at rest. An additional force is now applied to the block and it accelerates downward at '\(g\)' \((g =10~\text{m/s}^2)\). At this moment, the force exerted by the spring on the block will be:
1. \(10~\text{N}\)
2. \(15~\text{N}\)
3. \(20~\text{N}\)
4. zero
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| 1. | \(\dfrac g 3\) to left, \(g\) upward, \(g\) downward. |
| 2. | zero, zero, \(g\) downward. |
| 3. | zero, \(g\) upward, \(g\) downward. |
| 4. | \(g\) to right, zero, \(g\) downward. |
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| 1. | \(k_1x-k_2x=ma \) |
| 2. | \(\dfrac{k_1k_2}{k_1+k_2}x=ma \) |
| 3. | \(k_1x+k_2x=ma \) |
| 4. | \(\dfrac{k_1k_2}{k_1-k_2}=ma \) |
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The extension in the spring, in equilibrium, is:
1. \(1~\text{cm}\)
2. \(2~\text{cm}\)
3. \(0.5~\text{cm}\)
4. \(\sqrt2~\text{cm}\)
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- 1(current)
Q. No.
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