Select Question Set:
- 1(current)
Q. No.A particle \((P)\) of mass \(m\) is placed on the axis of a uniform circular ring of radius \(R\) and mass \(M.\) Its distance \((OP)\) from the centre \((O)\) of the ring is equal to \(R.\) Let the net gravitational field at the centre of the ring be \(g.\) Then, the gravitational potential energy of the interaction of the system is:
| 1. | \(-MgR\) | 2. | \(-mgR\) |
| 3. | \(\dfrac{-MgR}{\sqrt2}\) | 4. | \(\dfrac{-mgR}{\sqrt2}\) |
Subtopic: Gravitational Potential Energy |
Level 3: 35%-60%
To unlock all the explanations of this course, you need to be enrolled.
Hints
To unlock all the explanations of this course, you need to be enrolled.
Select Question Set:
- 1(current)
Q. No.
© 2026 GoodEd Technologies Pvt. Ltd.