[Cr(NH3)6]3+ is paramagnetic ,while Ni(CN)42- is diamagnetic because:

1. Electrons in the 3d orbitals remain unpaired in Ni(CN)42-
2. Electrons in the 3d orbitals remain unpaired in [Cr(NH3)6]3+
3. Electrons in the 3p orbitals remain unpaired in [Cr(NH3)6]3+
4. Electrons in the 3p orbitals remain unpaired in Ni(CN)42-

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The correct electronic configuration of the central atom in K4FeCN6  based on crystal field theory is:

1. \(e^4 ~t_{2 g}^2 \) 2. \(t_{2 g}^4 ~e_g^2 \)
3. \(t_{2 g}^6 ~e_g^0 \) 4. \(e^3 ~t^3_{2g}\)
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The correct splitting diagram of d orbitals in an octahedral crystal field is:

1. 2.
3. 4.  
None of these.
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The electronic configuration that represents the maximum magnetic moment is:

1. d3

2. d2

3. d8

4. d6(high spin)

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The low spin complex among the following is:

1. \(\mathrm{Fe}(\mathrm{CN})_6^{3-} \) 2. \(\mathrm{Co}\left(\mathrm{NO}_2\right)_6^{3-} \)
3. \(\mathrm{Mn}(\mathrm{CN})_6^{3-} \) 4. All of the above
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For a tetrahedral complex [MCl4]2-, the spin-only magnetic moment is 3.83 B.M. The element M is:

1. Co

2. Cu

3. Mn

4. Fe

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The geometry and magnetic properties of [NiCl4]2-, respectively, are : 

1. Tetrahedral, Paramagnetic

2. Tetrahedral, Diamagnetic

3. Square planar, Paramagnetic

4. Square planar, Diamagnetic  

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The complex ion among the following that cannot absorb visible light is:

1. [Ni(CN)4]2-

2. [Cr(NH3)6]3+

3. [Fe(H2O)6]2+

4. [Ni(H2O)6]2+

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An ion, among the following, that has a magnetic moment of 2.84 BM is:
(At. no. Ni = 28, Ti = 22, Cr = 24, Co = 27)

1. Ni2+
2. Ti3+
3. Cr2+
4. Co2+

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The complex among the following with the highest value of crystal field splitting energy is :

1. \(\left[Fe \left(H_{2} O\right)_{6}\right]^{+ 3}\) 2. \(\left[Ru \left( CN \right)_{6}\right]^{3 -}\)
3. \(\left[Fe \left(H_{2} O\right)_{6}\right]^{+ 2}\) 4. \(\left[Fe \left(NH_{3}\right)_{6}\right]^{3 +}\)
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