Order, Molecularity and Mechanism Past Year (2019 onward - NTA Papers) MCQs Chemical Kinetics Chemistry NEET Practice Questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, and PDF solved with answers

The following data is for a reaction between reactants A and B:

Rate mol $L^{-1}s^{-1}$	[A]	[B]
$2 \times10^{-3}$	0.1 M	0.1 M
$4 \times10^{-3}$	0.2 M	0.1 M
$1.6 \times10^{-2}$	0.2 M	0.2 M

The order of the reaction with respect to A and B, respectively are:

1. 1, 0
2. 0, 1
3. 1, 2
4. 2, 1

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For a certain reaction, the rate = $k[A]^2[B],$ when the initial concentration of A is tripled keeping the concentration of B constant, the initial rate would be:

1.	Increase by a factor of three
2.	Decrease by a factor of nine
3.	Increase by a factor of six
4.	Increase by a factor of nine

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The correct options for the rate law that corresponds to overall first order reaction is:

1.	$ Rate =k[A]^0[B]^2 $	2.	$ Rate =k[A][B] $
3.	$Rate=k[A]^{1 / 2}[B]^2 $	4.	$Rate =k[A]^{-1 / 2}[B]^{3 / 2}$

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The given graph is a representation of the kinetics of a reaction.

The y and x axes for zero and first-order reactions, respectively are

1.	zero order (y=rate and x=concentration), first order (y=rate and x=t_1/2)
2.	zero order (y=concentration and x=time), first order (y=t_1/2 and x = concentration)
3.	zero order (y=concentration and x= time), first order (y=rate constant and x= concentration)
4.	zero order (y=rate and x=concentration), first order (y=t_1/2 and x = concentration)

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The half-life for a zero-order reaction having 0.02 M initial concentration of reactant is 100 s. The rate constant (in mol L^–1 s^–1) for the reaction is:

1. $1.0 \times 10^{- 4}$

2. $2.0 \times 10^{- 4}$

3. $2.0 \times 10^{- 3}$

4. $1.0 \times 10^{- 2}$

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Rate mol \(L^{-1}s^{-1}\)	[A]	[B]
\(2 \times10^{-3}\)	0.1 M	0.1 M
\(4 \times10^{-3}\)	0.2 M	0.1 M
\(1.6 \times10^{-2}\)	0.2 M	0.2 M

1.	\( Rate =k[A]^0[B]^2 \)	2.	\( Rate =k[A][B] \)
3.	\(Rate=k[A]^{1 / 2}[B]^2 \)	4.	\(Rate =k[A]^{-1 / 2}[B]^{3 / 2}\)

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