The emf of the cell in which the following reaction takes place is:

Ni_(s)+2Ag⁺(0.002 M) →Ni²⁺(0.160 M) + 2Ag_(s)
( Given that \(E_{cell}^{o}\)= 1.05 V)

1. E_cell= 9.14 V
2. E_cell= 0.0914 V
3. E_cell= 0.00914 V
4. E_cell= 0.914 V