On electrolysis of dilute sulphuric acid using Platinum (Pt) electrode, the product obtained at the anode will be:

1. Oxygen gas

2. ${\mathrm{H}}_2\mathrm{S}$ gas

3. ${\mathrm{SO}}_2$ gas

4. Hydrogen gas 

If the  $E_{cell}^{}$ $0$for a given reaction has a negative value, then which of the following gives the correct relationship for the values of $∆G^0$ $$ $and$ $$ $$ $K_{eq}$?

1.  $∆{\mathrm{G}}^0<0;$ ${\mathrm{K}}_{\mathrm{eq}}>1$

2.  $∆{\mathrm{G}}^0<0;$ ${\mathrm{K}}_{\mathrm{eq}}<1$

3.  $∆{\mathrm{G}}^0>0;$ ${\mathrm{K}}_{\mathrm{eq}}<1$

4.  $∆{\mathrm{G}}^0>0;$ ${\mathrm{K}}_{\mathrm{eq}}>1$