The relative lowering of vapour caused by dissolving 71.3 g of a substance in 1000 g of water is 7.13 x 10-3. The molecular mass of the substance is-
1. 180 g mol-1
2. 18 g mol-1
3. 1.8 g mol-1
4. 360 g mol-1
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe vapour pressure of a pure liquid solvent A is 0.80 atm. When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm.
Mole fraction of the component B in the solution is:
1. | 0.50 | 2. | 0.75 |
3. | 0.40 | 4. | 0.25 |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyLowering in vapour pressure is the highest for:
1. 0.2 m urea
2. 0.1 m glucose
3. 0.1 m MgSO4
4. 0.1 m BaCl2
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyAn aqueous solution is 1.00 molal in KI. The vapour pressure of the solution can be increased by:
1. Addition of NaCl
2. Addition of Na2SO4
3. Addition of 1.00 molal Kl
4. Addition of water
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe equal weight of a solute is dissolved in an equal weight of two solvents A and B to form a very dilute solution. The relative lowering of vapour pressure for solution B has twice the relative lowering of vapour pressure for solution A.
If and are the molecular weights of solvents A and B respectively, then:
1. =
2. = 2
3. = 4
4. = 2
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyPrefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology