One mole of sugar is dissolved in three moles of water at 298 K. The relative lowering of vapour pressure is:

1. 0.25 2. 0.15
3. 0.50 4. 0.33
Subtopic:  Relative Lowering of Vapour Pressure |
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If 8 g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapor pressure to 80 %, the molar mass (in g mol–1) of the solute is:

[Molar mass of n-octane is 114 g mol–1]

1. 40 2. 60
3. 80 4. 20
Subtopic:  Relative Lowering of Vapour Pressure |
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At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
1. 100 oC
2. 102 oC
3. 103 oC
4. 101 oC
Subtopic:  Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
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The largest freezing point depression among the following 0.10 m solutions is shown by:

1. \(\mathrm{KCl}\) 2. \(\mathrm{C_6H_{12}O_6}\)
3. \(\mathrm{Al}_2(\mathrm{SO_4})_3\) 4. \(\mathrm{K_2SO_4}\)
Subtopic:  Relative Lowering of Vapour Pressure |
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An aqueous solution is 1.00 molal in KI. The vapour pressure of the solution can be increased by:

1. Addition of NaCl

2. Addition of Na2SO4

3. Addition of 1.00 molal Kl

4. Addition of water

Subtopic:  Relative Lowering of Vapour Pressure |
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The vapour pressure of a solvent decreased by 10 mm of Hg when a non-volatile solute was added to the solvent. The mole fraction of the solute in solution is 0.2. What would be the mole fraction of the solvent if the decrease in vapour pressure is 20 mm of Hg:
1. 0.2
2. 0.4
3. 0.6
4  0.8

Subtopic:  Relative Lowering of Vapour Pressure |
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