A=4i+4j-4k and B=3i+j+4k, then angle between vectors A and B is:

(1)  180°

(2)  90°

(3)  45°

(4)  0°

Subtopic:  Resultant of Vectors |
 77%
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If vectors A=cosωti^+sinωtj^ and B=cos(ωt2)i^+sin(ωt2)j^ are functions of time. Then, at what value of t are they orthogonal to one another?
1. t=π4ω
2. t=π2ω
3. t=πω
4. t=0

Subtopic:  Scalar Product |
 61%
From NCERT
NEET - 2015
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Six vectors a through f have the magnitudes and directions indicated in the figure. Which of the following statements is true? 

1. b+c=f

2. d+c=f

3. d+e=f

4. b+e=f

Subtopic:  Resultant of Vectors |
 75%
From NCERT
AIPMT - 2010
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A and B are two vectors and θ is the angle between them. If |A×B|=3(AB), then the value of θ will be:

1. 60 2. 45
3. 30 4. 90
Subtopic:  Scalar Product | Vector Product |
 80%
From NCERT
AIPMT - 2007
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If a curve is governed by the equation y = sinx, then the area enclosed by the curve and x-axis between x = 0 and x = π is (shaded region):

              
1. 1 unit
2. 2 units
3. 3 units
4. 4 units

Subtopic:  Integration |
 59%
From NCERT
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The acceleration of a particle starting from rest varies with time according to relation, a=α t+β. The velocity of the particle at time instant t is: (Here, a=dvdt)

1. αt2+βt

2. αt2+βt2

3. αt22+βt

4. 2αt2+βt

Subtopic:  Integration |
 85%
From NCERT
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The displacement of the particle is zero at t=0 and at t=t it is x. It starts moving in the x-direction with a velocity that varies as v=kx, where k is constant. The velocity will: (Here, v=dxdt)

1. vary with time.
2. be independent of time.
3. be inversely proportional to time.
4. be inversely proportional to acceleration.
Subtopic:  Integration |
 52%
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The acceleration of a particle is given as a=3x2.  At t=0,v=0 and x=0. It can then be concluded that the velocity at t=2 s will be: (Here, a=vdvdx)
1. 0.05 m/s
2. 0.5 m/s
3. 5 m/s
4. 50 m/s

Subtopic:  Integration |
 62%
From NCERT
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The acceleration of a particle is given by a=3t at t=0, v=0, x=0. The velocity and displacement at t=2 sec will be:
(Here, a=dvdt and v=dxdt)
1. 6 m/s,4 m
2. 4 m/s,6 m
3. 3 m/s,2 m
4. 2 m/s,3 m

Subtopic:  Integration |
 85%
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The 9 kg block is moving to the right with a velocity of 0.6 m/s on a horizontal surface when a force F, whose time variation is shown in the graph, is applied to it at time t = 0. Calculate the velocity v of the block when t= 0.4s. The coefficient of kinetic fricton is μk=0.3[This question includes concepts from Work, Energy & Power chapter]

1. 0.6 m/s

2. 1.2 m/s

3. 1.8 m/s

4. 2.4 m/s

Subtopic:  Friction |
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