CH₃CH₂NH₂ contains a basic NH₂ group, but CH₃CONH₂ does not, because;

1. acetamide is amphoteric in character

2. in CH₃CH₂NH₂ the electron pair on N-atom is delocalized by resonance

3. in CH₃CH₂NH₂ there is no resonance, while in acetamide the lone pair of electron on N-atom is delocalized and therefore less available for protonation

4. none of the above

Dehydration of an amide gives:

1. Cyanide

2. Amine

3. Isocyanide

4. Fatty acid

Tertiary nitro compounds cannot show tautomerism because:

1. they are very stable

2. isomerises to give sec. nitro compounds

3. do not have labile H-atom

4. they are highly eactive

A secondary amine is:

1. a compound with two -NH₂ groups

2. a compound with 2 carbon atoms and a -NH₂ group

3. a compound with a -NH₂ group on the carbon atom in number 2 position

4. a compound in which 2 of the hydrogens of NH₃ have been replaced by alkyl or aryl groups

Compound that will undergo Hoffmann reaction is-

1. RCONHCH₃

2. RCOONH₄

3. RCONH₂

4. RCONHOH

The reagent required to convert acetamide into methyl amine is :

1. NaOH/ Br₂

2. Sodalime

3. Hot conc. H₂SO₄

4. PCl₅

The above reaction is an example of....

1. Intermolecular C-N coupling
2. Intramolecular C-N coupling
3. Intermolecular N-N coupling
4. Intramolecular N-N coupling

The product[A] formed in the reaction; $2{\mathrm{C}}_5{\mathrm{H}}_5-\mathrm{CN}\underset{{\mathrm{Et}}_2\mathrm{O}}{\overset{\mathrm{Na}}{\to }} \left[\mathrm{A}\right] \mathrm{is}:\mathrm{C}$

1. 

2. 

3. 

4. 

The end product in the following sequence of reactions is -

${\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NH}}_2\stackrel{{\mathrm{HNO}}_2}{\to }A \stackrel{{\mathrm{PCl}}_5}{\to }B\stackrel{{\mathrm{NH}}_3}{\to }C?$
$$

1. Ethyl cyanide

2. Ethylamine

3. Methylamine

4. Acetamide

Alkyl halide (RX) on treatment with KCN followed by reduction leads to the formation of:

1. RNH₂

2. RCH₂NH₂

3. RH + NH₃

4. RCH₃ + N₂