Size of nucleus is of the order of

(1) ${10}^{-10} \mathrm{m}$            

(2) ${10}^{-15 }\mathrm{m}$

(3) ${10}^{-12} \mathrm{m}$             

(4) ${10}^{-19} \mathrm{m}$

For effective nuclear forces, the distance should be

(1) ${10}^{-10} \mathrm{m}$         

(2) ${10}^{-13} \mathrm{m}$

(3) ${10}^{-15} \mathrm{m}$         

(4) ${10}^{-20} \mathrm{m}$

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particle) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931 MeV) :

(1) 28.4 MeV               

(2) 20.8 MeV

(3) 27.3 MeV               

(4) 14.2 MeV

Atomic power station at Tarapore has a generating capacity of 200 MW. The energy generated in a day by this station is

(1) 200 MW               

(2) 200 J

(3) $4800\times {10}^6 \mathrm{J}$          

(4) $1728\times {10}^{10}$ J

One nanogram of matter converted into energy will give- 

(1) 90 J                     

(2) $9\times {10}^3 \mathrm{J}$ 

(3) $9\times {10}^{10} \mathrm{J}$            

(4) \(9\times 10^{4}~J\)

The binding energy of deuteron ${}_1{}^2\mathrm{H}$ is 1.112 MeV per nucleon and an $\mathrm{\alpha }$-particle ${}_2{}^4\mathrm{He}$ has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction ${}_1{}^2\mathrm{H}+{}_1{}^2\mathrm{H}\to {}_2{}^4\mathrm{He}+\mathrm{Q}$, the energy Q released is

(1) 1 MeV             

(2) 11.9 MeV

(3) 23.8 MeV         

(4) 931 MeV

Binding energy of a nucleus is:
(1) Energy given to its nucleus during its formation

(2) Total mass of nucleus converted to energy units

(3) Loss of energy from the nucleus during its formation

(4) Total K.E. and P.E. of the nucleons in the nucleus

Which of the following pairs is an isobar 

(1) ${}_1\mathrm{H}_1$ and ${}_1\mathrm{H}_2$               

(2) ${}_1\mathrm{H}_2$ and ${}_1\mathrm{H}_3$

(3) ${}_6\mathrm{C}_{12}$ and ${}_6\mathrm{C}_{13}$              

(4) ${}_{15}\mathrm{P}_{30}$ and ${}_{14}\mathrm{Si}_{30}$

Equivalent energy of mass equal to 1 a.m.u. is

(1) 931 KeV               

(2) 931 eV

(3) 931 MeV               

(4) 9.31 MeV

The mass number of a nucleus is equal to the number of

(1) Electrons it contains           

(2) Protons it contains

(3) Neutrons it contains           

(4) Nucleons it contains