In a reaction, 

${\mathrm{CH}}_2={\mathrm{CH}}_2$$\underset{\mathrm{acid}}{\overset{\mathrm{Hypochlorous}}{\to }}$M$\stackrel{\mathrm{R}}{\to }$$\underset{{\mathrm{CH}}_2\mathrm{OH}}{\underset{|}{{\mathrm{CH}}_2\mathrm{OH}}}$

M = molecules, R = reagent. M and R are

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$ and NaOH

2. ${\mathrm{CH}}_2\mathrm{Cl}.{\mathrm{CH}}_2\mathrm{OH}$ and aq. ${\mathrm{NaHCO}}_3$

3. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}$ and HCl

4.  and heat

When 3,3-dimethyl-2-butanol is heated with conc.${\mathrm{H}}_2{\mathrm{SO}}_4$, the major product obtained is -

1. 2,3-Dimethyl-2-butene

2. 3,3-Dimethyl-2-butene

3. 2,3-Dimethyl-1-butene

4. Cis and trans-isomers of 2,3-Dimethyl-2-butene

During ozonolysis of ${\mathrm{CH}}_2={\mathrm{CH}}_2$ if hydrolysis is made in absence of Zn dust the products formed are:

1. HCHO                                  2. HCOOH 

3. ${\mathrm{CH}}_3\mathrm{OH}$                                4. ${\mathrm{CH}}_2{\mathrm{OHCH}}_2\mathrm{OH}$

In the above reaction, X is:

1. ${\mathrm{HNO}}_3$ 

2. ${\mathrm{O}}_2$

3. ${\mathrm{O}}_3$

4. ${\mathrm{KMnO}}_4$

The major product of the following reaction is:

 +  Alc.KOH $\to$  ?   

1. Butene

2. But-2-ene

3. Butane 

4. But-1-yne

An alkene, obtained by the dehydration of an alcohol (A), on ozonolysis gives two molecules of acetaldehyde for every molecule of alkene. The alcohol (A) is:

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{OH}$ 

2. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}$

3. ${\mathrm{CH}}_3\mathrm{CH}={\mathrm{CHCH}}_2\mathrm{OH}$   

4.  

Gammexane (a $\mathrm{\gamma }$-isomer) is:

1. BHC
2. Benzene hexachloride
3. Lindane
4. All of the above

In the following reaction the catalyst used is:

         $\to$${\mathrm{C}}_6{\mathrm{H}}_6$ + 3${\mathrm{H}}_{\mathrm{2 \; \; }}$

1. ${\mathrm{Cr}}_2{\mathrm{O}}_3$                                      2. $A{l}_2{\mathrm{O}}_3$

3. Zn dust                                    4. ${\mathrm{Cr}}_2{\mathrm{O}}_3$ and $A{l}_2{\mathrm{O}}_3$

Silver acetylide when heated with HCl gives:

1. ${\mathrm{C}}_2{\mathrm{H}}_2$

2. ${\mathrm{H}}_2$

3. ${\mathrm{C}}_2{\mathrm{H}}_4$ 

4. ${\mathrm{C}}_6{\mathrm{H}}_6$

$\hspace{0.17em}\mathrm{R}-{\mathrm{CH}}_2-{\mathrm{CCl}}_2-\mathrm{R}\stackrel{\mathrm{Reagent}}{\to }$$\mathrm{R}-\mathrm{C}\equiv \mathrm{C}-\mathrm{R}$.
The reagent is: 

1. Na                                     
2. HCl in ${\mathrm{H}}_2\mathrm{O}$
3. NaNH₂               
4. Zn in alcohol