A body revolved around the sun 27 times faster than the earth. What is the ratio of their radii?
1. 1/3
2. 1/9
3. 1/27
4. 1/4
The period of the moon’s rotation around the earth is nearly 29 days. If the moon’s mass were 2 fold, its present value and all other things remained unchanged, the period of the moon’s rotation would be nearly:
1.
2.
3.
4. 29 days
If two planets are at mean distances \(d_1\) and \(d_2\) from the sun and their frequencies are \(n_1\) and \(n_2\) respectively, then:
1. \(n^2_1d^2_1= n_2d^2_2\)
2. \(n^2_2d^3_2= n^2_1d^3_1\)
3. \(n_1d^2_1= n_2d^2_2\)
4. \(n^2_1d_1= n^2_2d_2\)
1. | Kepler's law of areas still holds. |
2. | Kepler's law of period still holds. |
3. | Kepler's law of areas and period still hold. |
4. | Neither the law of areas nor the law of period still hold. |
A planet is revolving around the sun as shown in an elliptical path.
The correct option is:
1. The time taken in travelling DAB is less than that for BCD
2. The time taken in travelling DAB is greater than that for BCD
3. The time taken in travelling CDA is less than that for ABC
4. The time taken in travelling CDA is greater than that for ABC
In an elliptical orbit under gravitational force, in general
1. Tangential velocity is constant
2. Angular velocity is constant
3. Radial velocity is constant
4. Areal velocity is constant
Earth is revolving around the sun, if the distance of the Earth from the Sun is reduced to 1/4th of the present distance then the present year length reduced to -
1.
2.
3.
4.
Two satellite are revolving around the earth with velocities and and in radii and respectively. Then -
1.
2.
3.
4.
If orbital velocity of planet is given by , then -
1.
2.
3.
4.
The mass of a planet that has a moon whose time period and orbital radius are T and R respectively can be written as -
1.
2.
3.
4.