The phase difference between the current and voltage of LCR circuit in series combination at resonance is
1. 0
2. π/2
3. π
4. –π
In a series resonant circuit, the ac voltage across resistance R, inductance L and capacitance C are 5 V, 10 V and 10 V respectively. The ac voltage applied to the circuit will be
1. 20 V
2. 10 V
3. 5 V
4. 25 V
In a series LCR circuit, resistance R = 10Ω and the impedance Z = 20Ω. The phase difference between the current and the voltage is
1. 30°
2. 45°
3. 60°
4. 90°
In the circuit shown below, the AC source has voltage V=20cos(ωt) volts with ω=2000 rad/sec. The amplitude of the current is closest to:
1. 2 A
2. 3.3 A
3. 2√5
4. √5 A
In an ac circuit the reactance of a coil is √3 times its resistance, the phase difference between the voltage across the coil to the current through the coil will be:
1. π/3
2. π/2
3. π/4
4. π/6
The power factor of an ac circuit having resistance (R) and inductance (L) connected in series and an angular velocity ω is
1. R/ωL
2. R/(R2+ω2L2)1/2
3. ωL/R
4. R/(R2−ω2L2)1/2
An inductor of inductance L and resistor of resistance R are joined in series and connected by a source of frequency ω.
The power dissipated in the circuit is:
1. (R2+ω2L2)V
2. V2R(R2+ω2L2)
3. V(R2+ω2L2)
4. √R2+ω2L2V2
In an LCR circuit, the potential difference between the terminals of the inductance is 60 V, between the terminals of the capacitor is 30 V and that between the terminals of the resistance is 40 V. The supply voltage will be equal to:
1. 50 V
2. 70 V
3. 130 V
4. 10 V
In a circuit, L,C and R are connected in series with an alternating voltage source of frequency f. The current leads the voltage by 45∘. The value of C will be:
1. | 12πf(2πfL+R) | 2. | 1πf(2πfL+R) |
3. | 12πf(2πfL−R) | 4. | 1πf(2πfL−R) |
In an LR-circuit, the inductive reactance is equal to the resistance R of the circuit. An e.m.f. E=E0cos(ωt) applied to the circuit. The power consumed in the circuit is:
1. E20R
2. E202R
3. E204R
4. E208R