1. | execute simple harmonic motion about the origin. |
2. | move to the origin and remain at rest. |
3. | move to infinity. |
4. | execute oscillatory but not simple harmonic motion. |
An electrostatic line of force in the xy plane is given by equation x2+y2=1. A particle with unit positive charge, initially at rest at the point x=1,y=0 in the xy plane will:
1. | Not move at all |
2. | Will move along straight line |
3. | Will move along the circular line of force |
4. | The data given in the question is contradictory |
A positively charged ball hangs from a silk thread. We put a positive test charge q0 at a point and measure F/q0, then it can be predicted that the electric field strength E
(1) > F/q0
(2) = F/q0
(3) < F/q0
(4) Cannot be estimated
A solid metallic sphere has a charge +3Q. Concentric with this sphere is a conducting spherical shell having charge –Q. The radius of the sphere is a and that of the spherical shell is b (b > a). What is the electric field at a distance R(a < R < b) from the centre
(1) Q2πε0R
(2) 3Q2πε0R
(3) 3Q4πε0R2
(4) 4Q4πε0R2
A point charge q is placed at a distance a2 directly above the centre of a square of side a. The electric flux through the square (i.e. one face) is:
1. qε0
2. qπε0
3. q4ε0
4. q6ε0
Two infinitely long parallel wires having linear charge densities λ1 and λ2 respectively are placed at a distance of R meters. The force per unit length on either wire will be (K=14πε0)
(1) K2λ1λ2R2
(2) K2λ1λ2R
(3) Kλ1λ2R2
(4) Kλ1λ2R
The charge on 500 cc of water due to protons will be:
1. 6.0 × 1027 C
2. 2.67 × 107 C
3. 6 × 1023 C
4. 1.67 × 1023 C
In the given figure two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that θ is so small that tanθ≈sinθ, then for equilibrium x is equal to
(1) (q2L2πε0mg)13
(2) (qL22πε0mg)13
(3) (q2L24πε0mg)13
(4) (q2L4πε0mg)13
Three positive charges of equal value q are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in
(1) (2)
(3) (4)
Two equal charges are separated by a distance d. A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force when
(1) x=d√2
(2) x=d2
(3) x=d2√2
(4) x=d2√3