When connected across the terminals of a cell, a voltmeter measures 5V and a connected ammeter measures 10 A of current. A resistance of 2 ohms is connected across the terminals of the cell. The current flowing through this resistance will be :

(1) 2.5 A

(2) 2.0 A

(3) 5.0 A

(4) 7.5 A

Subtopic:  Kirchoff's Voltage Law |
 59%
From NCERT
PMT - 1997
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In the circuit shown here, E1 = E2 = E3 = 2 V and R1 = R2 = 4 ohms. The current flowing between points A and B through battery E2 is 

(1) Zero

(2) 2 amp from A to B

(3) 2 amp from B to A

(4) None of the above

Subtopic:  Grouping of Cells |
 52%
From NCERT
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In the circuit shown below, \(E_1 = 4.0~\text{V}\), \(R_1 = 2~\Omega\)\(E_2 = 6.0~\text{V}\), \(R_2 = 4~\Omega\) and \(R_3 = 2~\Omega\). The current \(I_1\) is:

    

1. \(1.6\) A

2. \(1.8\) A

3. \(1.25\) A

4. \(1.0\) A

Subtopic:  Grouping of Cells |
 53%
From NCERT
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The potential difference across \(8\) ohms resistance is \(48\) volts as shown in the figure below. The value of potential difference across \(X\) and \(Y\) points will be:

   
1. \(160\) volt
2. \(128\) volt
3. \(80\) volt
4. \(62\) volt

Subtopic:  Kirchoff's Voltage Law |
 62%
From NCERT
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Two resistances R1 and R2 are made of different materials. The temperature coefficient of the material of R1 is α and of the material of R2 is –β. The resistance of the series combination of R1 and R2 will not change with temperature, if R1/ R2 equals :

(1) αβ

(2) α+βαβ

(3) α2+β2αβ

(4) βα

Subtopic:  Derivation of Ohm's Law |
 57%
From NCERT
PMT - 1997
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An ionization chamber with parallel conducting plates as anode and cathode has 5×107 electrons and the same number of singly-charged positive ions per cm3. The electrons are moving at 0.4 m/s. The current density from anode to cathode is 4μA/m2. The velocity of positive ions moving towards cathode is :

(1) 0.4 m/s

(2) 16 m/s

(3) Zero

(4) 0.1 m/s

Subtopic:  Current & Current Density |
From NCERT
PMT - 1992
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A wire of resistance 10 Ω is bent to form a circle. P and Q are points on the circumference of the circle dividing it into a quadrant and are connected to a Battery of 3 V and internal resistance 1 Ω as shown in the figure. The currents in the two parts of the circle are 

(1) 623A  and  1823A

(2) 526A  and 1526A

(3) 425A  and  1225A

(4) 325A  and  925A

Subtopic:  Combination of Resistors |
 64%
From NCERT
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In the given circuit, it is observed that the current I is independent of the value of the resistance R6. Then the resistance values must satisfy 

(1) R1R2R5=R3R4R6

(2) 1R5+1R6=1R1+R2+1R3+R4

(3) R1R4=R2R3

(4) R1R3=R2R4=R5R6

Subtopic:  Combination of Resistors |
 80%
From NCERT
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In the given circuit, with a steady current, the potential drop across the capacitor must be :

(1) V

(2) V / 2

(3) V / 3

(4) 2V / 3

Subtopic:  Kirchoff's Voltage Law |
From NCERT
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A wire of length L and 3 identical cells of negligible internal resistances are connected in series. Due to current, the temperature of the wire is raised by ΔT in a time t. A number N of similar cells is now connected in series with a wire of the same material and cross–section but of length 2 L. The temperature of the wire is raised by the same amount ΔT in the same time t. The value of N is- 

(1) 4

(2) 6

(3) 8

(4) 9

Subtopic:  Grouping of Cells |
 68%
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