In order to pass 10% of the main current through a moving coil galvanometer of 99 ohms, the resistance of the required shunt is :

1. 9.9 Ω

2. 10 Ω

3. 11 Ω

4. 9 Ω

When a \(12~\Omega\) resistor is connected in parallel with a moving coil galvanometer, its deflection reduces from \(50\) divisions to \(10\) divisions. What will be the resistance of the galvanometer?
1. \(24~\Omega\)
2. \(36~\Omega\)
3. \(48~\Omega\)
4. \(60~\Omega\)

A voltmeter has a resistance of G ohms and range V volts. The value of resistance used in series to convert it into a voltmeter of range nV volts is :

1. nG

2. $(n-1)G$

3. $\frac{G}{n}$ 

4. $\frac{G}{(n-1)}$

Which of the following statement is wrong:

1. Voltmeter should have high resistance

2. Ammeter should have low resistance

3. Ammeter is placed in parallel across the conductor in a circuit

4. Voltmeter is placed in parallel across the conductor in a circuit

A moving coil galvanometer has a resistance of 50 Ωand gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A :

1. 50/99 Ω in series

2. 50/99 Ω in parallel

3. 0.01 Ω in series

4. 0.01 Ω in parallel

The resistance of an ideal voltmeter is 

1. Zero

2. Very low

3. Very large

4. Infinite

The net resistance of a voltmeter should be large to ensure that :

A galvanometer having a resistance of \(8~\Omega\) is shunted by a wire of resistance \(2~\Omega\). If the total current is \(1~\text{A}\), the part of it passing through the shunt will be:
1. \(0.25~\text{A}\)
2. \(0.8~\text{A}\)
3. \(0.2~\text{A}\)
4. \(0.5~\text{A}\)

A voltmeter of resistance 1000 Ω gives full-scale deflection when a current of 100 mA flow through it. The shunt resistance required across it to enable it to be used as an ammeter reading 1 A at full-scale deflection is :

1. 10000 Ω

2. 9000 Ω

3. 222 Ω

4. 111 Ω

If an ammeter \(A\) reads \(2\) A and the voltmeter \(V\) reads \(20\) V, what is the value of resistance \(R\)? (Assuming finite resistances of ammeter and voltmeter)